更改循环

Question

我试图创建一个循环，当随机数匹配输入的相同索引时，值会发生变化，并为每个后续循环保持这种状态。

input = gets.chomp
tries_left = 12
while(tries_left > 0)
tries_left -= 1
computer = 4.times.map do rand(0..6) end.join

  if computer[0] == input[0]
    computer[0] = input[0]
 end
end

在第一个循环之后的代码中，存储到input [0]的值重置。

computer = 4.times.map do rand(0..6) end.join
 input = gets.chomp
  tries_left = 12
    while(tries_left > 0)
    tries_left -= 1

      if computer[0] == input[0]
        computer[0] = input[0]
     end

如果我将计算机带出这样的循环，它每次都会生成相同的随机数。除了已经匹配的东西之外，我每次都需要它来生成新的数字。

Answer 1

如果你使myEARApp.ear - myWarApp.war -- a lot of libs from the war module -- myEJBmodule.jar -- myAdditionalJarModule.jar - lib/ -- only a few extra jar modules referenced in ear/pom.xml -- missing: logback, ehcache, etc. - myEJBmodule.jar - myAdditionalJarModule.jar - otherDependencyOfmyAdditionalJarModule.jar 成为一个字符串数组，你可以freeze来防止它进一步修改，然后replace计算机中的内容与它不匹配时指数：

computer

然后当你运行脚本时：

input = gets.chomp
tries_left = 12

computer = Array.new(4) { '' }
# setting the srand to 1234, the next 48 calls to 'rand(0..6)' will always
# result in the following sequence:
# 3, 6, 5, 4, 4, 0, 1, 1, 1, 2, 6, 3, 6, 4, 4, 2, 6, 2, 0, 0, 4, 5, 0, 1,
# 6, 6, 2, 0, 3, 4, 5, 2, 6, 2, 3, 3, 0, 1, 3, 0, 3, 2, 3, 4, 1, 3, 3, 3
# this is useful for testing things are working correctly,
# but take it out for 'live' code
srand 1234
while tries_left > 0
  # no need to keep iterating if we've generated all the correct values
  if computer.all?(&:frozen?)
    puts "won #{computer.inspect} in #{12 - tries_left} tries"
    break
  end

  tries_left -= 1
  computer.each.with_index do |random, index|
    # generate a new random number here unless they guessed correctly previously
    random.replace(rand(0..6).to_s) unless random.frozen?

    # if they've guessed the new random number, mark the string so they we
    # don't update it
    random.freeze if random == input[index]
  end

  puts "#{computer.inspect} has #{computer.count(&:frozen?)} correct numbers"
end