我正在创建一个社交网络,为用户提供更改其个人资料图片或保持相同的选项(默认)。我问了一个关于此的问题并得到了一个答案,帮助我将图片保存到我的上传文件夹中,而不是如何更改用户的个人资料照片。
用户将单击选择文件按钮,然后在选择文件时,他们将单击显示更改个人资料图片的按钮。当他们完成所有这些操作时,我希望默认图片更改为用户选择的图片。有人可以帮帮我吗 ?
profile.php:
<form id="form2" action="upload.php" method="post" enctype="multipart/form-data">
<p id="p1">Change profile picture:</p> <br />
<input type="file" name="fileToUpload" id="fileToUpload"><br />
<br><input id="sub1" type="submit" value="Change profile picture" name="submit"><br />
</form>
<!-- Trigger the Modal -->
<img id="myImg" src="default.png" width="200" height="150">
<!-- The Modal -->
<div id="myModal" class="modal">
<!-- The Close Button -->
<span class="close" onclick="document.getElementById('myModal').style.display='none'">×</span>
<!-- Modal Content (The Image) -->
<img class="modal-content" id="img01">
<!-- Modal Caption (Image Text) -->
<div id="caption"></div>
</div>
<script>
// Get the modal
var modal = document.getElementById('myModal');
// Get the image and insert it inside the modal - use its "alt" text as a caption
var img = document.getElementById('myImg');
var modalImg = document.getElementById("img01");
var captionText = document.getElementById("caption");
img.onclick = function(){
modal.style.display = "block";
modalImg.src = this.src;
captionText.innerHTML = this.alt;
}
// Get the <span> element that closes the modal
var span = document.getElementsByClassName("close")[0];
// When the user clicks on <span> (x), close the modal
span.onclick = function() {
modal.style.display = "none";
}
</script>
更新!!
我已更新我的代码以保存图像,然后将其保存在数据库中,但所有这些代码都在将其保存在我的图像文件夹中,而不是将其保存在我的数据库中。请帮帮我。
upload.php的:
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
include("connect.php");
include("auth_login.php");
$target_dir = "images/uploads/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
// Check if image file is a actual image or fake image
if(isset($_POST["change"])) {
move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file);
$q = mysqli_query ($conn, "UPDATE users SET userPic = '".$_FILES['fileToUpload']
['name']."' WHERE username = '" . $username . "'");
if($check !== false) {
echo "File saved - " . $check["mime"] . ".";
$uploadOk = 1;
} else {
echo "File is not an image.";
$uploadOk = 0;
}
}
答案 0 :(得分:0)
解决此问题的最佳方法可能是散列文件并将散列存储在数据库中,然后使用散列作为名称保存文件。
这样您就可以创建像
这样的每个用户 insert into user (username, photo) values ('me', 'default_photo_hash')
然后当用户更新他的照片时,您可以散列新照片,保存并
update user (photo) values ('new_photo_hash') where username='me'
答案 1 :(得分:0)
我在自己的博客上有这样的东西(这是php代码!我在页面上打印时遇到一些问题):
if(isset($_FILES['profile']) === true){
if(empty($_FILES['profile']['name']) === true){
echo "<div class='img-file-error'>Please choose a file!</div>";
}else{
$allowed = array('jpg', 'jpeg', 'gif', 'png');
$file_name = $_FILES['profile']['name'];
$file_extn = strtolower(end(explode('.', $file_name)));
$file_temp = $_FILES['profile']['tmp_name'];
if(in_array($file_extn, $allowed) === true){
change_profile_image($session_user_id, $file_temp, $file_extn);
header('Location: settings');
exit();
}else{
echo "<div class='img-file-error'>Incorrect file type!<br>
Allowed types: ";
echo implode(', ',$allowed);
echo ".</div>";
}
}
}
if(!empty($user_data['profile'])){
echo '<img id="previewImg" class="img-settings" width="250px" src="', $user_data['profile'], '" alt="',$user_data['first_name'],'\'s profile image">';
}
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和js文件:
function onFileSelect(e){
var f = e.target.files[0];
if(f.type.match(/image.*/)){
var reader = new FileReader;
place = document.getElementById("previewImg");
reader.readAsDataURL(f);
reader.onload = function(e){
place.src = e.target.result;
}
}
else {
alert('You can chose only pictures');
};
};
if(window.File && window.FileReader && window.FileList && window.Blob){
document.querySelector("input[type=file]").addEventListener("change", onFileSelect, false);
}else{
console.warn( "Your browser does not support FileAPI");
};
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