Question

我正在尝试使用ajax提交我的表单，似乎无法让它工作。我尝试过不同的方法，但数据仍未发送到数据库。以下是我的代码

形式

<form action='sendquestion.php' method='post' id="sendQform" enctype="multipart/form-data">
    <input type='text' name='searchQuestion' id='searchQuestion'placeholder='Enter your question'><br>
    <input type="text" name="user" id="user" value="<?php echo ''.$_SESSION['log_id'].'';?>" style="display: none">
    <input type="text" name="qDate" id="qDtae" value="<?php echo date('d/M/Y');?>" style="display: none">
    <input type="text" name="status" id="status" value="0" style="display: none">
    <label for='sendSearchQuestion'><i class='fa fa-send'></i></label>
    <input type="submit" name="sendSearchQuestion" id="sendSearchQuestion" value="Send">
</form>

的Ajax

$('#sendQform').submit(function(e) {
    e.preventDefault();
    var $form = $(this), url = $form.attr("action");

    var posting = $.post(url, {searchQuestion: $('#searchQuestion').val(), user: $('#user').val(), status: $('#status').val(), qDate: $('#qDate').val()});
    posting.done(function(data) {
        alert("success");
    });
});

PHP

<?php
session_start();
require_once ("db.php");
$db = new MyDB();

if (isset($_POST['sendSearchQuestion']))
{
    $question = strip_tags(@$_POST['searchQuestion']);
    $askid = htmlentities($_POST['user'], ENT_QUOTES, 'UTF-8');
    $status = strip_tags(@$_POST['status']);
    $date = htmlentities($_POST['qDate'], ENT_QUOTES, 'UTF-8');

    $sql = $db->prepare("INSERT INTO userquestions (userid, question, status, dates) VALUES (?, ?, ?, ?)");
    $sql->bindParam(1, $askid, SQLITE3_INTEGER);
    $sql->bindParam(2, $question, SQLITE3_TEXT);
    $sql->bindParam(3, $status);
    $sql->bindParam(4, $date);

    $result = $sql->execute();

    if ($result)
    {
        echo "true";
    }
    else
    {
        echo "false";
    }
}
?>

为什么这不起作用。感谢。

Answer 1

您的逻辑测试适用于sendSearchQuestion，您的fild是searchQuestion

更改

if (isset($_POST['sendSearchQuestion']))

到

if (isset($_POST['searchQuestion']))

Ajax没有发送到数据库

1 个答案: