我想抓一个网页:https://www.justdial.com/Mumbai/Dairy-Product-Retailers-in-Thane/nct-10152687
我需要所有商店名称,电话号码及其地址
的数据但我只能做到10岁 导致加载滚动网页所需的其他项目
我的代码:
import requests
import bs4
crawl_url = requests.get('https://www.justdial.com/Mumbai/Dairy-Product-
Retailers-in-Thane/nct-10152687', headers={'User-Agent': 'Mozilla/5.0'})
crawl_url.raise_for_status()
soup = bs4.BeautifulSoup(crawl_url.text, 'lxml')
for elems in soup.find_all('span', class_="jcn"):
select_a = elems.select('a')
for links in select_a:
href = links.get('href')
res = requests.get(href, headers={'User-Agent': 'Mozilla/5.0'})
xsoup = bs4.BeautifulSoup(res.text, 'lxml')
Name = xsoup.select('.fn')
tel = xsoup.select('.tel')
add = xsoup.select('.adrstxtr')
a = Name[0]
b = tel[0]
c = add[0]
print(a.getText())
print("--"*10)
print(b.getText())
print("--"*10)
print(c.getText())
print("=="*25)
当我们向下滚动页面时,其他项目加载 所以我想知道如何获得我想要的任何数据/项目
我尝试了this
但是没有安静地理解嘛,我也没有那个POST方法:/
如果需要更多信息告诉我
答案 0 :(得分:2)
t.m.adam给出的解决方案 这是代码
import requests
import bs4
def spider(max_pages):
page = 1
while page < max_pages:
url = "https://www.justdial.com/Mumbai/Dairy-Product-Retailers-in-
Thane/nct-10152687/page-%s" % page
crawl_url = requests.get(url, headers={'User-Agent': 'Mozilla/5.0'})
crawl_url.raise_for_status()
soup = bs4.BeautifulSoup(crawl_url.text, 'lxml')
for elems in soup.find_all('span', class_="jcn"):
select_a = elems.select('a')
for links in select_a:
href = links.get('href')
res = requests.get(href, headers={'User-Agent':
'Mozilla/5.0'})
xsoup = bs4.BeautifulSoup(res.text, 'lxml')
Name = xsoup.select('.fn')
tel = xsoup.select('.tel')
add = xsoup.select('.adrstxtr')
a = Name[0]
b = tel[0]
c = add[0]
print(a.getText())
print("--"*10)
print(b.getText())
print("--"*10)
print(c.getText())
print("=="*25)
page += 1
spider(3)