Question

这是代码我运行但不工作你可以解决这个错误

IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[fPartnersDebt]') AND type in (N'FN', N'IF', N'TF', N'FS', N'FT'))
    DROP FUNCTION [dbo].[fPartnersDebt]

/****** Object:  UserDefinedFunction [dbo].[fPartnersDebt]    Script Date: 03/07/2012 16:02:01 ******/
SET ANSI_NULLS ON

SET QUOTED_IDENTIFIER ON

exec('CREATE PROCEDURE [dbo].[fPartnersDebt]')
(   
    @StartDate datetime
    ,@EndDate datetime
    ,@CompanyName nvarchar(100)
    ,@Account nvarchar(100)
    ,@Reference nvarchar(max)
    ,@ShowClosedDocuments bit
)
RETURNS TABLE 
AS
    RETURN 
        (SELECT 
             t1.Name, t1.Bulstat, t1.Amount, t1.IsVat
         FROM 
             (SELECT 
                  c.CompanyID, c.Name AS [Name], c.IsVat, c.Bulstat AS [Bulstat],
                  SUM((ad.Amount + ad.RefAmount) * ad.[Sign]) AS [Amount]
              FROM 
                  Companies c
              JOIN 
                  AccountingDetails ad 
              JOIN 
                  Accounts a 
              JOIN 
                  AccountCategories ac ON ac.AccountCategoryID = a.AccountCategoryID
                  ON ad.AccountID = a.AccountID
              JOIN 
                  Accountings acc ON ad.AccountingID = acc.AccountingID
                  ON ad.CompanyID = c.CompanyID
              LEFT JOIN 
                  [References] r ON acc.OptionalReferenceID = r.ReferenceID
              WHERE 
                  ac.TypeIdentifier IN (4, 6, 7, 8, 9, 20, 33, 54, 10, 12, 13, 14, 15, 19, 34, 55) 
                  AND Name LIKE @CompanyName 
                  AND (a.Number = @Account OR a.Number LIKE @Account + '/%' OR (Len(@Account) < 3 AND a.Number LIKE @Account + '%'))
                  AND acc.AccountingDate >= @StartDate 
                  AND acc.AccountingDate <= @EndDate
                  AND (ISNULL(r.[Description], '') LIKE @Reference + '%')
              GROUP BY 
                  c.CompanyID, c.Name, c.Bulstat, c.IsVat) t1
    WHERE 
        @ShowClosedDocuments = 1 OR t1.Amount <> 0
)

Answer 1

是的，只需要添加＆＃39; @＆在定义变量名之前

<div ng-app="" ng-init="name='abc'">
<p>Input something in the input box:</p>

<p>Name : <input type="text" ng-model="name" placeholder="Enter name here">
</p>
<h1>Hello @{{name}}</h1>

</div>

其工作

为什么angular的语法在Laravel应用程序中不起作用？

1 个答案: