Question

我有很少NSMutableArrays，例如arr1，arr2，arr3，arr4。如何将所有NSMutableArrays合并在一起？或者有多少方法可以多次追加到一个数组中？

示例：

arr = [[NSMutableArray alloc] init];
//first loop
for(condition){
    [arr addObject:firstLoopValue];
}
//second loop
for(condition){
    [arr addObject:secondLoopValue];
}
//third loop
for(condition){
    [arr addObject:thirdLoopValue];
}

最后的结果{firstLoopValue...secondLoopValue...thirdLoopValue}

我是iOS的新手，为什么不确定它是否可行。提前致谢

修改我尝试过以下两种方式：

rCodeArr = [[NSMutableArray alloc] init];
rDateArr = [[NSMutableArray alloc] init];
rAmountArr = [[NSMutableArray alloc] init];

jCodeArr = [[NSMutableArray alloc] init];
jDateArr = [[NSMutableArray alloc] init];
jAmountArr = [[NSMutableArray alloc] init];
jBalanceArr = [[NSMutableArray alloc] init];

NSArray *component = [journal getComponents:custCode];
for(int i = 0; i < [component count]; i++){

    list = [component objectAtIndex:i];

    NSArray *timestamp = [list.jDate componentsSeparatedByString:@" "];
    NSString *splitdate = timestamp[0];

    [jCodeArr addObject:list.jCode];
    [jDateArr addObject:splitdate];
    [jAmountArr addObject:list.jAmount];
    [jBalanceArr addObject:list.jOutstanding];
}
NSArray *rcom = [receipt getComponents:custCode];
for(int j = 0; j < [rcom count]; j++){

    rList = [rcom objectAtIndex:j];

    NSArray *rtime = [rList.rDate componentsSeparatedByString:@" "];
    NSString *rsplit = rtime[0];

    [rCodeArr addObject:rList.rCode];
    [rDateArr addObject:rsplit];
    [rAmountArr addObject:rList.rAmount];
    [rBalanceArr addObject:@"N/A"];
}

lblOneArray = [NSMutableArray arrayWithArray:rCodeArr];

    [lblOneArray addObjectsFromArray:jCodeArr];
    lblTwoArray = [NSMutableArray arrayWithArray:rDateArr];

    [lblTwoArray addObjectsFromArray:jDateArr];
    lblThreeArray = [NSMutableArray arrayWithArray:rAmountArr];

    [lblThreeArray addObjectsFromArray:jAmountArr];
    lblFourArray = [NSMutableArray arrayWithArray:jBalanceArr];
    [lblFourArray addObjectsFromArray:rBalanceArr];

和

lblOneArray = [[NSMutableArray alloc] init];
lblTwoArray = [[NSMutableArray alloc] init];
lblThreeArray = [[NSMutableArray alloc] init];
lblFourArray = [[NSMutableArray alloc] init];
[lblOneArray addObjectsFromArray:rCodeArr];
[lblOneArray addObjectsFromArray:jCodeArr];

[lblTwoArray addObjectsFromArray:rDateArr];
[lblTwoArray addObjectsFromArray:jDateArr];

[lblThreeArray addObjectsFromArray:jAmountArr];
[lblThreeArray addObjectsFromArray:jAmountArr];

[lblFourArray addObjectsFromArray:rBalanceArr];
[lblFourArray addObjectsFromArray:jBalanceArr];

但是它仍然在崩溃消息*****由于未捕获的异常终止应用程序＆＃39; NSRangeException＆＃39;，原因：＆＃39; * - [__ NSArrayM objectAtIndex：] ：索引5超出界限[0 .. 4]＆＃39;

注意所有这些都是NSMutableArray

Answer 1

您可以通过添加如下所示的所有数组来创建最终数组

@RequestMapping(method = RequestMethod.GET)
public ResponseEntity<List<SomeObject>> someMethod(HttpServletRequest request, @RequestParam(required = false) MultiValueMap<String, String> params) {

     String url = request.getRequestURL().toString() + (request.getQueryString() == null ? "" : "?" + request.getQueryString());
}

它没有崩溃，因为我检查了以下代码

NSMutableArray *newArray = [[NSMutableArray alloc] init];

[newArray addObjectsFromArray:firstArray];

[newArray addObjectsFromArray:secondArray];

Answer 2

要组合多个数组，您可以使用第一个数组的元素初始化数组，然后从中添加元素：

NSMutableArray* arr1 = [NSMutableArray arrayWithArray: firstLoopValue];
[arr1 addObjectsFromArray: secondLoopValue];
[arr1 addObjectsFromArray: thirdLoopValue];
[arr1 addObjectsFromArray: forthLoopValue];

Answer 3

只做

arr = [[NSMutableArray alloc] init];
[arr addObjectsFromArray:anArray1];
[arr addObjectsFromArray:anArray2];
[arr addObjectsFromArray:anArray3];

Objective C如何合并多个NSMutableArray？

3 个答案: