我是异步编程的新手。我正在做一个小POC,我想看看greenlets
对共享对象的行为。我写了这段代码 -
from gevent import monkey, sleep
from gevent import Greenlet
monkey.patch_all(thread=False, socket=False)
class Events:
def __init__(self):
self.num = 0
self.limit = 10
self.bulk_records = []
def start(self, task_number=0):
count = 0
print("Task: %s started" % task_number)
while count != 10:
self.bulk_records.append(task_number)
sleep(0.1)
if len(self.bulk_records) == self.limit:
print("%s, Task %s, outputting list: %s" % (self.num, task_number, self.bulk_records))
self.bulk_records[:] = []
self.num += 1
count += 1
print("Task - %s, count - %s" % (task_number, count))
def run_test():
event = Events()
tasks = [Greenlet.spawn(event.start, i) for i in range(5)]
print("Num tasks - %s" % len(tasks))
[task.run() for task in tasks]
print("End")
if __name__ == '__main__':
run_test()
它提供以下输出: -
Num tasks - 5
Task: 0 started
Task: 1 started
Task: 2 started
Task: 3 started
Task: 4 started
0, Task 0, outputting list: [0, 1, 2, 3, 4, 0, 1, 2, 3, 4]
1, Task 0, outputting list: [0, 1, 2, 3, 4, 0, 1, 2, 3, 4]
2, Task 0, outputting list: [0, 1, 2, 3, 4, 0, 1, 2, 3, 4]
3, Task 0, outputting list: [0, 1, 2, 3, 4, 0, 1, 2, 3, 4]
4, Task 0, outputting list: [0, 1, 2, 3, 4, 0, 1, 2, 3, 4]
Task - 0, count - 10
Task: 1 started # This is not expected
Task - 1, count - 10
Task - 2, count - 10
Task - 3, count - 10
Task - 4, count - 10
5, Task 1, outputting list: [1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
Task - 1, count - 10
End
Process finished with exit code 0
代码按预期工作,但最终发生了一些奇怪的事情,任务1再次启动,相应的函数start
再次执行。
不确定这是否是有效行为,或者我在代码中缺少的内容,以防止Greenlet
重新开始。
谢谢是提前
答案 0 :(得分:1)
与线程API相反,线程API需要创建一个线程对象并调用start()
方法,gevent.spawn
既进行Greenlet实例化,又安排Greenlet在一次调用中运行。
因此,不需要在greenlet对象上调用run()
(在大多数情况下可能非常错误)。
等待完成的任务由joinall(list of greenlets)
完成。调用之后,所有的绿色组件都已准备就绪(已死,是否成功)。