PHP通过图像传输id

Question

你好我得到的id是“$ id”而不是int id我想发生的是基本上它将会转到“showImage.php”中图像的完整大小

$xml = simplexml_load_file("source.xml", NULL, LIBXML_NOCDATA);


foreach ($xml->shopitem as $shopitem) {

  echo  $shopitem->item_id;
}

万一你想知道这是html

<?php
while($row = mysqli_fetch_array($result)) {
    $id = $row[0];


echo "<tr>";

    echo "<td>".$row[0]."</td>";
echo "<td>".$row[1]."</td>";
echo "<td>".$row[2]."</td>";
echo "<td>".$row[3]."</td>";
echo "<td>".$row[4]."</td>";
echo "<td>".$row[5]."</td>";
echo "<td>".$row[7]."</td>";
echo "<td>".$row[8]."</td>";
echo "<td>".$row[9]."</td>";
echo "<td>".$row[10]."</td>";
  echo '<td>
 <a href="showImage.php?id=$id"> <img id="$id" src="data:image/jpeg;base64,'.base64_encode($row[11] ).'" height="200" width="200"  /> </a> 
                           </td>  ';
?>