我有两张桌子
tbl_TimeEntries
EmployeeID int,
StartDateTime datetime,
EndDateTime datetime
tbl_Crew_Employees
CrewID,
EmployeeID,
StartDate,
EndDate
我还有一个查询可以产生每位员工每天工作的小时数,但我也希望包括当天员工所在的工作人员。
SELECT tbl_TimeEntries.EmployeeID,
SUM(DATEDIFF(SECOND, StartDateTime, EndDateTime) / 60.0
/ 60.0) as Hours,
CAST(StartDateTime AS date) as WorkDate
FROM tbl_TimeEntries
GROUP BY tbl_TimeEntries.EmployeeID, CAST(StartDateTime AS date)
ORDER BY CAST(StartDateTime AS date)
我不确定如何在此查询中包含CrewID,因为tbl_Crew_Employees使用StartDate和EndDate(意味着员工是从StartDate到EndDate的员工)。我要么需要扩展StartDate / EndDate范围,要么使用某种我不知道的SQL魔法。
以下是来自tbl_Crew_Employees,tbl_TimeEntries和添加了所需列数据的当前查询的数据示例。 EmployeeID 88代表样本中的两个不同的工作人员。
CrewID EmployeeID StartDate EndDate
13 11 2013-03-30 2013-05-12
12 88 2013-01-02 2013-04-18
12 66 2013-01-02 2013-06-30
13 88 2013-04-19 2013-04-21
11 111 2013-01-02 2013-04-28
EmployeeID StartDateTime EndDateTime
11 2013-04-18 08:00 2013-04-18 12:00
11 2013-04-18 12:30 2013-04-18 18:30
111 2013-04-18 10:00 2013-04-18 12:00
111 2013-04-18 12:30 2013-04-18 18:30
88 2013-04-18 11:00 2013-04-18 12:00
88 2013-04-18 12:30 2013-04-18 19:30
66 2013-04-18 10:00 2013-04-18 12:00
66 2013-04-18 12:30 2013-04-18 18:30
11 2013-04-20 08:00 2013-04-20 12:00
11 2013-04-20 12:30 2013-04-20 18:00
111 2013-04-20 10:00 2013-04-20 12:00
111 2013-04-20 12:30 2013-04-20 18:30
88 2013-04-20 11:00 2013-04-20 12:00
88 2013-04-20 12:30 2013-04-20 19:30
66 2013-04-20 10:00 2013-04-20 12:00
66 2013-04-20 12:30 2013-04-20 17:00
EmployeeID Hours WorkDate CrewID(desired)
11 10.00 2013-04-18 13
88 8.00 2013-04-18 12
66 8.00 2013-04-18 12
111 8.00 2013-04-18 11
11 7.50 2013-04-20 13
88 8.00 2013-04-20 13
66 6.50 2013-04-20 12
111 8.00 2013-04-20 11
答案 0 :(得分:1)
应该是一个简单的连接。
declare @tbl_Crew_Employees table(CrewID int, EmployeeID int, StartDate date, EndDate date)
insert into @tbl_Crew_Employees
values
(13,11,'2013-03-30','2013-05-12'),
(12,88,'2013-01-02','2013-04-18'),
(12,66,'2013-01-02','2013-06-30'),
(13,88,'2013-04-19','2013-04-21'),
(11,111,'2013-01-02','2013-04-28')
declare @tbl_TimeEntries table (EmployeeID int, StartDateTime datetime, EndDateTime datetime)
insert into @tbl_TimeEntries
values
(11,'2013-04-18 08:00','2013-04-18 12:00'),
(11,'2013-04-18 12:30','2013-04-18 18:30'),
(111,'2013-04-18 10:00','2013-04-18 12:00'),
(111,'2013-04-18 12:30','2013-04-18 18:30'),
(88,'2013-04-18 11:00','2013-04-18 12:00'),
(88,'2013-04-18 12:30','2013-04-18 19:30'),
(66,'2013-04-18 10:00','2013-04-18 12:00'),
(66,'2013-04-18 12:30','2013-04-18 18:30'),
(11,'2013-04-20 08:00','2013-04-20 12:00'),
(11,'2013-04-20 12:30','2013-04-20 18:00'),
(111,'2013-04-20 10:00','2013-04-20 12:00'),
(111,'2013-04-20 12:30','2013-04-20 18:30'),
(88,'2013-04-20 11:00','2013-04-20 12:00'),
(88,'2013-04-20 12:30','2013-04-20 19:30'),
(66,'2013-04-20 10:00','2013-04-20 12:00'),
(66,'2013-04-20 12:30','2013-04-20 17:00')
SELECT
t.EmployeeID,
c.CrewID,
SUM(DATEDIFF(SECOND, t.StartDateTime, t.EndDateTime) / 60.0
/ 60.0) ,
CAST(t.StartDateTime AS date)
FROM @tbl_TimeEntries t
INNER JOIN
@tbl_Crew_Employees c on
c.EmployeeID = t.EmployeeID
and c.StartDate <= cast(t.StartDateTime as date)
and c.EndDate >= cast(t.EndDateTime as date)
GROUP BY t.EmployeeID, CAST(t.StartDateTime AS date), c.CrewID
ORDER BY CAST(t.StartDateTime AS date)
答案 1 :(得分:1)
试试这个:
SELECT
tbl_TimeEntries.employeeid
,SUM(DATEDIFF(SECOND, StartDateTime, EndDateTime) / 60.0 / 60.0) AS HOURS
,CAST(StartDateTime AS DATE) AS WorkDate
,tbl_Crew_Employees.crewid
FROM tbl_TimeEntries
INNER JOIN tbl_Crew_Employees ON tbl_timeentries.employeeid = tbl_Crew_Employees.employeeid
AND startdatetime >= startdate
AND enddatetime <= enddate
GROUP BY tbl_TimeEntries.employeeid
,tbl_Crew_Employees.crewid
,CAST(tbl_TimeEntries.StartDateTime AS DATE)
ORDER BY WorkDate