我想从图像中切出一个洞(带有透明部分的png)。背景有一个渐变。我首先尝试使用svg和mask但是这对我来说不起作用,因为这会使孔中的渐变与外部渐变同步。
Afaik atm使用svg&s无法在图像中切出透明孔。 由于浏览器兼容性,无法使用Css剪辑路径。
所以我决定切换到canvas和js。但只是在图像中绘制一个透明圆圈没有任何效果。似乎必须有更先进的处理。
我对这个问题越来越绝望了。任何帮助表示赞赏。
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>test - image processing</title>
<script
src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js">
</script>
<style>
body{
background: red;
background: -webkit-linear-gradient(left top, red, yellow);
background: -o-linear-gradient(bottom right, red, yellow);
background: -moz-linear-gradient(bottom right, red, yellow);
background: linear-gradient(to bottom right, red, yellow);
}
canvas{
display: block;
margin:100px auto;
}
</style>
</head>
<body>
<div class="canvas-wrapper">
<canvas id="canvas" ></canvas>
</div>
<script>
$(document).ready(function () {
showImage();
function showImage() {
var ctx = document.getElementById('canvas').getContext('2d');
var image = new Image();
// adjust the image path
image.src = 'yourImagePathHere';
image.onload = function () {
document.getElementById('canvas').width = image.width;
document.getElementById('canvas').height = image.height;
ctx.drawImage(image, 0, 0);
var imgData = ctx.getImageData(0, 0, canvas.width, canvas.height);
for (var i = 0; i < imgData.data.length; i += 4) {
// how to process?
imgData.data[i] = imgData.data[i];
imgData.data[i + 1] = imgData.data[i+1];
imgData.data[i + 2] = imgData.data[i+2];
imgData.data[i + 3] = imgData.data[i+3];
}
ctx.putImageData(imgData, 0, 0);
};
}
});
</script>
答案 0 :(得分:0)
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>test - image processing</title>
<script
src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js">
</script>
<style>
body{
background: red;
background: -webkit-linear-gradient(left top, red, yellow);
background: -o-linear-gradient(bottom right, red, yellow);
background: -moz-linear-gradient(bottom right, red, yellow);
background: linear-gradient(to bottom right, red, yellow);
}
canvas{
display: block;
margin:100px auto;
}
</style>
</head>
<body>
<div class="canvas-wrapper">
<canvas id="canvas" ></canvas>
</div>
<script>
$(document).ready(function () {
showImage();
function showImage() {
var ctx = document.getElementById('canvas').getContext('2d');
var image = new Image();
// adjust the image path
image.src = 'yourImagePathHere';
image.onload = function () {
document.getElementById('canvas').width = image.width;
document.getElementById('canvas').height = image.height;
ctx.drawImage(image, 0, 0);
var imgData = ctx.getImageData(0, 0, canvas.width, canvas.height);
for (var i = 0; i < imgData.data.length; i += 4) {
// how to process?
imgData.data[i] = imgData.data[i];
imgData.data[i + 1] = imgData.data[i+1];
imgData.data[i + 2] = imgData.data[i+2];
imgData.data[i + 3] = imgData.data[i+3];
}
ctx.putImageData(imgData, 0, 0);
// this line does the magic, have a look at Amadans link for further possibilities
ctx.globalCompositeOperation='destination-out';
// here starts the circle form which is cutted out
ctx.beginPath();
ctx.fillStyle='';
ctx.arc(image.width/2,image.height/2,50,0,2*Math.PI);
ctx.fill();
};
}
});
</script>
答案 1 :(得分:0)
我不理解您声称SVG无法正常工作。使用SVG,你看起来很简单。
file_put_contents('logs.txt', "\n\n ====LOG Generated on... Date[" . date('h:i:s a d-m-Y') . "] ====== \n\n", FILE_APPEND | LOCK_EX);
&#13;
driver = webdriver.Chrome()
driver.get('http://www.ukathletics.com/schedule-list/#!/m-basebl/2016')
time.sleep(5)
driver.find_element_by_tag_name('body').send_keys(Keys.CONTROL + Keys.END)
time.sleep(5)
driver.find_element_by_tag_name('body').send_keys(Keys.CONTROL +Keys.END)
&#13;