HiveQl：基于字符串提取

Question

我有下表：

ID           | Keyword   |     Date

87NB  | skill,love,hate,funny,very funny | 02/19/2004

27YV  | funny,tiger,movie,king | 08/10/2014

92JK  | sun,light,funny,baby  | 06/27/2015

65TH  | moon,cow,bird,car     | 04/22/2017

从上表中，我想获得将“有趣”作为关键字的所有人的ID。结果将是

ID

87NB

27YV  

92JK 

Answer 1

你可以使用split然后使用函数array_contains

select ID from  yourtable where array_contains(split(Keyword, ","), "funny");

Answer 2

select  ID
from    t
where   find_in_set('funny',Keyword) > 0
;

+------+
| id   |
+------+
| 87NB |
+------+
| 27YV |
+------+
| 92JK |
+------+