Question

我想要在所有设备上的同一位置放置形状（矩形和圆形）（例如沿x的40％和y轴的20％）。

这里有一些代码：

class ColourSprite : SKSpriteNode {

var colour: String
var type: String



init(colour: String, categoryBitMask: UInt32, contactTestBitMask: UInt32,
     collisionBitMask : UInt32, type : String, point1: array, point2: array, point3: array, point4: array) {


    let shape = UIBezierPath()

    shape.addLine(to: CGPoint(point1[0], point1[1]))
    shape.addLine(to: CGPoint(point2[0], point2[1]))
    shape.addLine(to: CGPoint(point3[0], point3[1]))
    shape.addLine(to: CGPoint(point4[0], point4[1]))



    let texture = SKTexture() //I don't know what to do here

    self.colour = colour
    self.type = type

    super.init(texture: texture, color: UIColor.clear, size: texture.size())


    if type == "block" {
        self.physicsBody = SKPhysicsBody(rectangleOf: self.size)
    }
    else {
        self.physicsBody = SKPhysicsBody(circleOfRadius: self.size.width/2)
        self.isUserInteractionEnabled = true

    }
    self.physicsBody?.isDynamic = true
    self.physicsBody?.categoryBitMask = categoryBitMask
    self.physicsBody?.contactTestBitMask = contactTestBitMask
    self.physicsBody?.collisionBitMask = collisionBitMask
}

所以我想把所有的点（从gameScene类中以size.height / size.width的形式）传递给我的SKSpriteNode到类，这样它就会将它绘制到屏幕上的正确位置，但我不确定如何使精灵的质地更好，所以它可以保留其物理属性，任何想法？如果这没有任何意义，请告诉我。

Swift - 绘制形状并用作SKSpriteNode的精灵（bezier路径？）

0 个答案: