Question

尝试将此转换为C＃，但在设置为另一个常量时，它是否为某些十六进制值常量时会感到困惑。

Public Const STANDARD_RIGHTS_ALL = &H1F0000
Public Const SYNCHRONIZE = &H100000
Public Const KEY_CREATE_LINK = &H20
Public Const KEY_CREATE_SUB_KEY = &H4
Public Const KEY_ENUMERATE_SUB_KEYS = &H8
Public Const KEY_NOTIFY = &H10
Public Const KEY_QUERY_VALUE = &H1
Public Const KEY_SET_VALUE = &H2
Public Const KEY_READ = ((STANDARD_RIGHTS_READ Or _
                      KEY_QUERY_VALUE Or KEY_ENUMERATE_SUB_KEYS _
                     Or KEY_NOTIFY) And (Not SYNCHRONIZE))

C＃？：

public const int KEY_READ = ((STANDARD_RIGHTS_READ || KEY_QUERY_VALUE || KEY_ENUMERATE_SUB_KEYS || KEY_NOTIFY) & (!SYNCHRONIZE));

Answer 1

使用按位运算|，＆amp;和〜作为VB And，Or和Not的等效项。注意我将类型指定为uint（无符号整数），以避免由于.NET（more information here）中int类型的内部表示而产生的副作用。

public const uint READ_CONTROL = 0x20000;
public const uint STANDARD_RIGHTS_READ = READ_CONTROL;
public const uint STANDARD_RIGHTS_ALL = 0x1F0000;
public const uint SYNCHRONIZE = 0x100000;
public const uint KEY_CREATE_LINK = 0x20;
public const uint KEY_CREATE_SUB_KEY = 0x4;
public const uint KEY_ENUMERATE_SUB_KEYS = 0x8;
public const uint KEY_NOTIFY = 0x10;
public const uint KEY_QUERY_VALUE = 0x1;
public const uint KEY_SET_VALUE = 0x2;
public const uint KEY_READ = (
    (STANDARD_RIGHTS_READ | KEY_QUERY_VALUE | KEY_ENUMERATE_SUB_KEYS | KEY_NOTIFY) 
    & (~SYNCHRONIZE)
);

vb6 ORing十六进制值常量？

1 个答案: