Question

我正在尝试将列表绑定到sqlalchemy中的原始SQL查询中的参数。 This post提出了使用psycopg2进行此操作的好方法。

some_ids = [1, 2, 3, 4]
query = "SELECT * FROM my_table WHERE id = ANY(:ids);"
engine.execute(sqlalchemy.sql.text(query), ids=some_ids)

但是，对于SQL Server pyodbc的环境，这似乎不起作用。只添加了一个"?"而不是4个。

sqlalchemy.exc.ProgrammingError: (pyodbc.ProgrammingError) 
('Invalid parameter type. param-index=0 param-type=tuple', 'HY105') 
[SQL: 'SELECT * FROM my_table WHERE id = ANY(?);'] [parameters: ((1, 2, 3, 4),)]

有没有办法让这项工作？如果可能，我想避免manually creating placeholders。

sqlalchemy version = 1.0.13，pyodbc version = 4.0.16

Answer 1

这似乎对我有用：

SELECT post_id, 
    '$order_company' AS Company,
    MAX(IF(meta_key = 'additional_volunteers', meta_value, '')) AS Volunteers,
    MAX(IF(meta_key = '_paid_date', meta_value, '')) AS Date,
    ...
FROM wp2_postmeta
WHERE post_id = (SELECT post_id FROM wp2_postmeta
                 WHERE meta_key = '_billing_company'
                   AND meta_value = '$order_company')

打印生成的SQL语句，然后打印查询结果

from sqlalchemy import create_engine
from sqlalchemy.sql import table, column, select, literal_column
engine = create_engine('mssql+pyodbc://SQLmyDb')
cnxn = engine.connect()
some_ids = [2, 3]
sql = select([literal_column('*')]).where(column('ID').in_(some_ids)).select_from(table('People'))
print(sql)
print('')
params = {":ID_" + str(x+1): some_ids[x] for x in range(len(some_ids))}
rows = cnxn.execute(sql, params).fetchall()
print(rows)

使用pyodbc替换SQLAlchemy SQL参数列表

1 个答案: