Question

如果“付款类别”列为Legal，我尝试创建一个使用Expense填充工具类型列的if语句。

但是，无论薪资类别如何，它都会将包含Legal Legal的所有内容展开。{/ p>

test={"Pay Category":["Indemnity","Indemnity","Indemnity","Indemnity","Expense","Expense","Expense","Medical"],"Description of Payment":["Legal","Legal","Legal","Legal","Legal","Legal","Frog","Legal",]}
test=pd.DataFrame(test)

test["Tool Type"]=""
if (test["Pay Category"]=="Medical") is not False: 
test["Tool Type"][test["Description of Payment"].str.contains("Pharmacy|Prescription|RX",case=False)]="Pharmacy"

if (test["Pay Category"]=='Expense') is not False:
test["Tool Type"][test["Description of Payment"].str.contains("Legal|Attorney|Court|Defense",case=False)]="Legal"

我的理解是，if (test["Pay Category"]=='Expense') is not False:是一个布尔值，它是True or False，它只应该执行if语句，如果标准＆＃34;不是假的＃34;满足了。我错过了什么？

布兰登

Answer 1

我认为您需要添加条件并将其与test["Tool Type"]="" m1 = test["Description of Payment"].str.contains("Pharmacy|Prescription|RX",case=False) m2 = test["Pay Category"]=="Medical" m3 = test["Description of Payment"].str.contains("Legal|Attorney|Court|Defense",case=False) m4 = test["Pay Category"]=="Expense" test.loc[m1 & m2, "Tool Type"]="Pharmacy" test.loc[m3 & m4, "Tool Type"]="Legal" print (test) Description of Payment Pay Category Tool Type 0 Legal Indemnity 1 Legal Indemnity 2 Legal Indemnity 3 Legal Indemnity 4 Legal Expense Legal 5 Legal Expense Legal 6 Frog Expense 7 Legal Medical（test['Tool Type'] = np.where(m1 & m2, 'Pharmacy', np.where(m3 & m4, 'Legal', '')) print (test) Description of Payment Pay Category Tool Type 0 Legal Indemnity 1 Legal Indemnity 2 Legal Indemnity 3 Legal Indemnity 4 Legal Expense Legal 5 Legal Expense Legal 6 Frog Expense 7 Legal Medical）链接起来：

test['Tool Type']  = np.select([(m1 & m2), (m3 & m4)], ['Pharmacy', 'Legal'], default='')
print (test)
  Description of Payment Pay Category Tool Type
0                  Legal    Indemnity          
1                  Legal    Indemnity          
2                  Legal    Indemnity          
3                  Legal    Indemnity          
4                  Legal      Expense     Legal
5                  Legal      Expense     Legal
6                   Frog      Expense          
7                  Legal      Medical

另一个双Apple's Documentation的解决方案：

SelectedDates

编辑：numpy.where评论的非常好的解决方案是使用unutbu

List

if语句重映射值

1 个答案: