当我回复$json2时，我的JSON Array会被返回，如：
[{"contact_phonenumber":"12345"}][{"contact_phonenumber":"67890"}][{"contact_phonenumber":"123456"}][{"contact_phonenumber":"78901"}][{"contact_phonenumber":"234567"}][{"contact_phonenumber":"8901234"}]
对我来说它看起来不像JSON Array，我确定我的循环出现了问题 - 也许是因为while嵌套在{ {1}}或者其他东西，但即使我改变它，我也会得到相同的结果。你能帮忙吗？
我希望for each成为：
JSON array这是我的代码：
[{"contact_phonenumber":"12345"}, {"contact_phonenumber":"67890"},
{"contact_phonenumber":"123456"}, {"contact_phonenumber":"78901"},{"contact_phonenumber":"234567"}, {"contact_phonenumber":"8901234"}]
编辑：非常感谢您的帮助，但现在当我按照您的大部分答案提出建议时 - 宣布<?php
require('dbConnect.php');
//this is the username in the user table
$Number = "+353872934480";
// get the username of the user in the user table, then get the matching user_id in the user table
// so we can check contacts against it
$query = "SELECT * FROM user WHERE username = ?";
$stmt = $con->prepare($query) or die(mysqli_error($con));
$stmt->bind_param('s', $Number) or die("MySQLi-stmt binding failed " . $stmt->error);
$stmt->execute() or die("MySQLi-stmt execute failed " . $stmt->error);
$result = $stmt->get_result();
while($row = $result->fetch_assoc()) {
//this is the corresponding user_id in the user table of the user
$user_id = $row["user_id"];
}
//post all contacts for user_id as a JSON array
$phonenumberofcontact = '["+11111","+222222","12345","67890","123456","78901","234567","8901234"]';
$array = json_decode($phonenumberofcontact);
//We want to check if contacts of user_id are also users of the app.
$query = "SELECT * FROM user WHERE username = ?";
$stmt2 = $con->prepare($query) or die(mysqli_error($con));
$stmt2->bind_param('s', $phonenumberofcontact) or die("MySQLi-stmt binding failed " . $stmt->error);
//for each value, call it $phonenumberofcontact
foreach($array as $value) {
$phonenumberofcontact = $value;
$stmt2->execute() or die("MySQLi-stmt execute failed " . $stmt2->error);
//match the phone numbers in the JSON Array against those in the user table
$result2 = $stmt2->get_result();
while($row = $result2->fetch_assoc()) {
//make an array called $results
//this is a matching number in user table and in the JSON Array
//call this username contact_phonenumber
$results = array();
$results[] = array(
'contact_phonenumber' => $row['username']
);
$json2 = json_encode($results);
echo $json2;
}
}
并在$results圈外回复json，我得到以下内容：
while你知道如何在没有空括号的情况下得到匹配的数字吗？而且，在开头和结尾只应该是方括号 - 就像JSON数组一样。
这是我的更新代码：
[][][{"contact_phonenumber":"12345"}][{"contact_phonenumber":"67890"}][{"contact_phonenumber":"123456"}][{"contact_phonenumber":"78901"}][{"contact_phonenumber":"234567"}][{"contact_phonenumber":"8901234"}]
答案 0 :(得分：5)
在results循环之外声明while数组，如下所示：
$results = array();
foreach ($array as $value)
{
$phonenumberofcontact = $value;
$stmt2->execute() or die ("MySQLi-stmt execute failed ".$stmt2->error);
$result2 = $stmt2->get_result();
while ($row = $result2->fetch_assoc()) {
if(!empty($row['username'])) {
$results[] = array('contact_phonenumber' => $row['username']);//remove extra ,
}
}
}
$json2 = json_encode($results);
echo $json2;
答案 1 :(得分：2)
在代码的以下部分中，您需要重新排列一些变量以获得所需的效果：
$results = array(); // Move this outside the loop
while ($row = $result2->fetch_assoc()) {
$results[] = array("contact_phonenumber" => $row["username"]);
}
// As well as these two line
$json2 = json_encode($results);
echo $json2;
答案 2 :(得分：1)
可能你可以改变你的阻止这样的东西：
$results = array();
while ($row = $result2->fetch_assoc()) {
//make an array called $results
//this is a matching number in user table and in the JSON Array
//call this username contact_phonenumber
$results[] = array(
'contact_phonenumber' => $row['username'],
);
}
$json2 = json_encode($results);
echo $json2;
答案 3 :(得分：0)
因为你在foreach循环中回显你的JSON字符串。 试试这个 -
<?php
require('dbConnect.php');
//this is the username in the user table
$Number = "+353872934480";
// get the username of the user in the user table, then get the matching user_id in the user table
// so we can check contacts against it
$query = "SELECT * FROM user WHERE username = ?";
$stmt = $con->prepare($query) or die(mysqli_error($con));
$stmt->bind_param('s', $Number) or die ("MySQLi-stmt binding failed ".$stmt->error);
$stmt->execute() or die ("MySQLi-stmt execute failed ".$stmt->error);
$result = $stmt->get_result();
while ($row = $result->fetch_assoc()) {
//this is the corresponding user_id in the user table of the user
$user_id = $row["user_id"];
}
//post all contacts for user_id as a JSON array
$phonenumberofcontact ='["+11111","+222222","12345","67890","123456","78901","234567","8901234"]';
$array = json_decode($phonenumberofcontact);
//We want to check if contacts of user_id are also users of the app.
$query = "SELECT * FROM user WHERE username = ?";
$stmt2 = $con->prepare($query) or die(mysqli_error($con));
$stmt2->bind_param('s', $phonenumberofcontact) or die ("MySQLi-stmt binding failed ".$stmt->error);
//for each value, call it $phonenumberofcontact
$i = 0;
$tempArray = array();
foreach ($array as $value)
{
$phonenumberofcontact = $value;
$stmt2->execute() or die ("MySQLi-stmt execute failed ".$stmt2->error);
//match the phone numbers in the JSON Array against those in the user table
$result2 = $stmt2->get_result();
while ($row = $result2->fetch_assoc()) {
//make an array called $results
//this is a matching number in user table and in the JSON Array
//call this username contact_phonenumber
$results = array();
$results[] = array(
'contact_phonenumber' => $row['username'],
);
$tempArray[$i] = $results;
$i++;
}
$json2 = json_encode($results);
echo $json2;
}
?>