Question

我只是一件快事。我启动时，我的页面出现了HTML 500错误，但我根本无法看到我的代码有什么问题。我正在尝试在我的网页上创建一个联系表单，只需获取详细信息并在用户单击表单时通过电子邮件发送给我。该页面将不会加载此代码。

            <form method="post">

                <input type="text" name="contact-name" placeholder="Name." required>
                <input type="email" name="contact-email" placeholder="Email." required>
                <input type="text" name="contact-subject" placeholder="Subject." required>
                <br><br>
                <textarea name="contact-content"></textarea>
                <div id="contact-btn-wrap">
                    <input type="submit" name="contact-submit" id="login-btn-signup" value="SEND EMAIL">
                </div>

            </form>
                <br><br><br><br>
                <div class="contact-me">danashton89@gmail.com | 07714709250</div>
            </div>
        </div>
        <div class="contact-img">
            <img src="/uploads/Portfolio/Level_Design/Unreal_Engine/Ice_Cove/icecastle_3.png">
        </div>


        <?php

            $contact-name = "";
            $contact-email = "";
            $contact-subject = "";
            $contact-content = "";

                if (isset($_POST['contact-submit'])) 
                {
                    $contact-name = mysqli_real_escape_string($con, $_POST['contact-name']);
                    $contact-email = mysqli_real_escape_string($con, $_POST['contact-email']);
                    $contact-subject = mysqli_real_escape_string($con, $_POST['contact-subject']);
                    $contact-content = mysqli_real_escape_string($con, $_POST['contact-content']); 

                        $to = "danashton89@gmail.com";
                        $subject = $contact-subject;
                        $txt = $contact-content;
                        $headers = "From: " . $contact-name . "<br>" . $contact-email . "\r\n";
                        $headers.= "MIME-version: 1.0\n";
                        $headers.= "Content-type: text/html; charset= iso-8859-1\n";

                    mail($to,$subject,$txt,$headers);
                }

        ?>

Answer 1

我认为您不能在变量名称中使用破折号（$ contact-name ...）

Answer 2

首先，你不能用' - '

在php中声明变量

变量名遵循与PHP中其他标签相同的规则。有效的变量名称以字母或下划线开头，后跟任意数量的字母，数字或下划线。作为正则表达式，它将表达为：'[a-zA-Z_ \ x7f- \ xff] [a-zA-Z0-9_ \ x7f- \ xff] *'

其次，您的连接var已定义？

最后，你能提供错误字符串吗？

PHP邮件链接

2 个答案: