Question

我正在尝试从SQLite数据库中检索一些数据。我正在使用JPA和EclipseLink作为提供程序，我正在尝试构建REST API。我有我的模型类，我在其中查询的类。 servcie和我构建URI的其余类。

这是我的模特课：

package com.vehicle.dao;



import java.util.ArrayList;
import java.util.List;

import javax.persistence.EntityManager;
import javax.persistence.EntityManagerFactory;
import javax.persistence.Persistence;
import javax.persistence.PersistenceContext;
import javax.persistence.Query;
import javax.persistence.criteria.CriteriaBuilder;
import javax.persistence.criteria.CriteriaQuery;
import javax.persistence.criteria.Root;

import com.vehicle.model.Vehicle;


public class VehicleDAO {

    EntityManagerFactory emfactory = Persistence.createEntityManagerFactory( "example" );

    EntityManager em = emfactory.createEntityManager( );


       public void fetchVehicle(){
           Query query = em.createQuery("Select v.name, v.model, v.purchasing_date from Vehicles v");
                      List<String> list = query.getResultList();

                      for(String e:list) {
                         System.out.println("Vehicle NAME :"+e);
                      }

       }


}

这是我的DAO课程：

package com.vehicle.service;


import java.util.ArrayList;

import com.vehicle.dao.VehicleDAO;
import com.vehicle.model.Vehicle;


public class VehicleService {

    VehicleDAO vehicleDao = new VehicleDAO();

    public void getDefaultVehicle() {
        System.out.println("BLAAAAAA");
       vehicleDao.fetchVehicle();
    }
}

这是从我的DAO类调用该方法的服务类：

package com.vehicle.rest;



import java.util.ArrayList;

import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.core.Response;

import com.vehicle.model.Vehicle;
import com.vehicle.service.VehicleService;


@Path("/vehicles")
public class VehicleRest {

VehicleService vehicleService = new VehicleService();

    @GET
    @Path("/getVehicles")
    @Produces(MediaType.APPLICATION_JSON)
    public void getDefaultVehicleInJSON() {
        System.out.println("BLAAAAAAA");
        vehicleService.getDefaultVehicle();
    }
}

这个类是我构建其余URI的类：

Aug 08, 2017 6:08:27 PM com.sun.jersey.spi.container.ContainerResponse mapMappableContainerException
SEVERE: The RuntimeException could not be mapped to a response, re-throwing to the HTTP container
java.lang.IllegalArgumentException: An exception occurred while creating a query in EntityManager: 
Exception Description: Problem compiling [Select v.name, v.model, v.purchasing_date from Vehicles v]. 
[7, 13] The state field path 'v.name' cannot be resolved to a valid type.
[15, 22] The state field path 'v.model' cannot be resolved to a valid type.
[24, 41] The state field path 'v.purchasing_date' cannot be resolved to a valid type.
[47, 55] The abstract schema type 'Vehicles' is unknown.

问题是，当我尝试在浏览器中运行它时，它会给我这个错误：

<?xml version="1.0" encoding="UTF-8" ?>
  <persistence xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
      xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
      version="2.0"
      xmlns="http://java.sun.com/xml/ns/persistence">
    <persistence-unit name="example" transaction-type="RESOURCE_LOCAL">
      <provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
      <class>com.vehicle.model.Vehicle</class>
       <exclude-unlisted-classes>true</exclude-unlisted-classes>
      <properties>
        <property name="javax.persistence.jdbc.driver" value="org.sqlite.JDBC" />
        <property name="javax.persistence.jdbc.url" value="jdbc:sqlite:C:/development.sqlite3" />
        <property name="eclipselink.logging.level" value="ALL" />
        <property name="eclipselink.ddl-generation" value="create-tables" />
      </properties>
    </persistence-unit>
 </persistence>

我不明白为什么。没有架构，它只是默认架构。

修改

这是我的persistence.xml：

CustomerView

提前致谢！

Answer 1

查询应为

Select v.name, v.model, v.purchasing_date from Vehicle v

您在问题中加了Vehicles。实体名称为Vehicle（与班级相同）。

JPA映射错误

1 个答案: