所以我有这张桌子。我怎么知道哪个员工来这里的时间最长?
create table Staff (
StaffId char(5) not null,
StaffName varchar(20) not null,
StaffPhone varchar(13),
StaffIc char(14),
JoinDate date,
primary key(StaffId),
constraint chk_StaffIc check (REGEXP_LIKE(StaffIc,'\d{6}\-\d{2}\-
\d{4}')),
constraint chk_StaffPhone check (REGEXP_LIKE(StaffPhone,'^01[0-9]-
\d{7}|\d{8}$'))
);
答案 0 :(得分:1)
时间最长,请使用top 1
并按JoinDate
升序排序。最短的将是下降:
select top 1
StaffId,
StaffName,
StaffPhone,
StaffIc,
JoinDate,
from Staff
order by JoinDate asc
答案 1 :(得分:0)
这会告诉你多长时间,也可能是月,年等等。
见DATEDIFF()
select top 1 staffid, staffname, DATEDIFF(day,joindate,getdate()) from Staff
order by joindate
这使用GETDATE()
来获取当天