Question

我希望在单击ListView中的项目时有一个上下文菜单

<ListView x:Name="resultsView" Grid.Column="1" Margin="10" Grid.Row="1" FontFamily="Verdana" FontSize="14">
        <ListView.ContextMenu>
            <ContextMenu FontFamily="Verdana" FontSize="14">
                <MenuItem Header="Open Folder" Click="openFolder_Click" FontFamily="Verdana" FontSize="14"/>
                <Separator/>
                <MenuItem Header="Copy Path" Click="copyPath_Click" FontFamily="Verdana" FontSize="14"/>
            </ContextMenu>
        </ListView.ContextMenu>

        <ListView.View>
            <GridView x:Name="gridView">
                <GridViewColumn x:Name="name" Header="Name" DisplayMemberBinding="{Binding Name}"/>
                <GridViewColumn x:Name="folder" Header="Folder" DisplayMemberBinding="{Binding Folder}"/>
                <GridViewColumn x:Name="location" Header="Path" DisplayMemberBinding="{Binding Location}"/>
            </GridView>
        </ListView.View>
</ListView>

以下是我如何向ListView添加项目（结果是SearchFolder的列表）：

results.Add(new SearchFolder { Name = Path.GetFileName(directory), Folder = Path.GetFileName(Path.GetDirectoryName(directory)), Location = directory });
resultsView.ItemsSource = results;

我的SearchFolder类

class SearchFolder
{
    public string Name { get; set; }

    public string Folder { get; set; }

    public string Location { get; set; }
}

如何创建ContextMenu，其中对ListView中单击的项执行操作（复制路径或打开文件夹）？

/ edit：这样，无论我在哪里右击，ContextMenu都会显示出来。但我找不到一种方法来访问点击的项目，这不起作用：

MenuItem temp = sender as MenuItem;
        if (temp != null)
        {
            ContextMenu anotherTemp = temp.Parent as ContextMenu;
            if (anotherTemp != null)
            {
                ListViewItem clickedItem = anotherTemp.PlacementTarget as ListViewItem;
                if (clickedItem != null)
                {
                    Console.WriteLine("Copy Path " + clickedItem.Name);
                }
            }
        }

Answer 1

ListView有一个事件“SelectionChanged”。使用此事件，您可以在此事件中设置所有代码并访问发件人中的项目。

代码：

<ListBox Grid.Row="1" Grid.Column="1" Margin="10,10,0,0" x:Name="lstBank" Style="{StaticResource TransparentListBox}" ItemTemplate="{StaticResource BankDataTemplate}"
                     MinHeight="35" MaxHeight="220" SelectionMode="Single" ItemsSource="{Binding Path=Banks}" ScrollViewer.HorizontalScrollBarVisibility="Disabled" SelectionChanged="lstBank_SelectionChanged" />

并在类文件中设置代码。

 private void lstBank_SelectionChanged(object sender, System.Windows.Controls.SelectionChangedEventArgs e) {

        }

Answer 2

我终于设法做了我想要的事情，我离开了以前的上下文菜单，并且能够在ContextMenu中的MenuItems的事件处理程序中使用以下代码获取项目

if(resultsView.SelectedIndex>-1)
        {
            SearchFolder selectedItem;
            selectedItem = (SearchFolder)resultsView.SelectedItem;
            //do stuff with selectedItem
        }

Answer 3

在点击事件处理程序上尝试此操作：

private void ItemRightClick(object sender, EventArgs e)
{
    MenuItem item = sender as MenuItem;
    if (item!= null)
    {
        ContextMenu contextMenu = item.Parent;
        Control clickedControl = contextMenu.SourceControl;
    }
}

没有检查过......

无论如何，另一种方法是使用＆＃39; MouseDown＆＃39;事件并检查点击的按钮是否正确：

private void ItemMouseDown(object sender, MouseEventArgs e)
{
     if(e.Button == MouseButtons.Right)
     {
          ListViewItem item = listView.GetItemAt(e.X, e.Y);
          if(item != null)
          {
             // here we have
          }
     }
}

ListView中的上下文菜单，选择项

3 个答案: