我正在尝试将手机中的所有联系人与我的应用程序相关联。然后从联系人应用程序启动我的应用程序在api< 23它工作正常。但是在api> 23中,联系人会被复制。所以让我知道有人试过这个!!这是我试过的......!
public class ContactsSync extends AsyncTask<String, String, String> {
@Override
protected String doInBackground(String... params) {
String name, number, id;
for (int i = 0; i <=mIDs.size(); i++) {
//name = mNames.get(i);
id = mIDs.get(i);
number = mNumbers.get(i);
ContactsManager.addContact(Paymoney.this, new MyContact(id, number));
}
return null;
}
@Override
protected void onPostExecute(String s) {
getContactDataAfter();
}
}
public static void addContact(Context context,MyContact contact){
ContentResolver resolver = context.getContentResolver();
boolean mHasAccount = isAlreadyRegistered(resolver, contact.Id);
if(mHasAccount){
} else {
ArrayList<ContentProviderOperation> ops = new ArrayList<ContentProviderOperation>();
// insert account name and account type
ops.add(ContentProviderOperation
.newInsert(addCallerIsSyncAdapterParameter(ContactsContract.RawContacts.CONTENT_URI, true))
.withValue(ContactsContract.RawContacts.ACCOUNT_NAME, Constants.ACCOUNT_NAME)
.withValue(ContactsContract.RawContacts.ACCOUNT_TYPE, Constants.ACCOUNT_TYPE)
.withValue(ContactsContract.RawContacts.AGGREGATION_MODE,
ContactsContract.RawContacts.AGGREGATION_MODE_DEFAULT)
.build());
ops.add(ContentProviderOperation
.newInsert(addCallerIsSyncAdapterParameter(ContactsContract.Data.CONTENT_URI, true))
.withValueBackReference(ContactsContract.Data.RAW_CONTACT_ID, 0)
.withValue(ContactsContract.Data.MIMETYPE, CommonDataKinds.Phone.CONTENT_ITEM_TYPE)
.withValue(CommonDataKinds.Phone.NUMBER, contact.number)
.build());
ops.add(ContentProviderOperation
.newInsert(addCallerIsSyncAdapterParameter(ContactsContract.Data.CONTENT_URI, true))
.withValueBackReference(ContactsContract.Data.RAW_CONTACT_ID, 0)
.withValue(ContactsContract.Data.MIMETYPE, MIMETYPE)
.withValue(ContactsContract.Data.DATA1, 12345)
.withValue(ContactsContract.Data.DATA2, "user")
.withValue(ContactsContract.Data.DATA3, "Send Money")
.build());
resolver.applyBatch(ContactsContract.AUTHORITY, ops);
答案 0 :(得分:0)
您需要明确将新$('#save').click(function() {
$.ajax({
type: 'POST',
contentType: 'application/json',
url: 'save_categories.php',
dataType: 'json',
data: JSON.stringify({'categories': $('.dd').nestable('serialize')}),
success: function(msg) {
alert(msg);
}
});
});
汇总到现有(原始)联系人中:
$json = json_decode(file_get_contents("php://input"));
$categories = $json->categories;
当然,您可以使用RawContact
在创建新ops.add(ContentProviderOperation.newUpdate(AggregationExceptions.CONTENT_URI)
.withValue(AggregationExceptions.TYPE, AggregationExceptions.TYPE_KEEP_TOGETHER)
.withValue(AggregationExceptions.RAW_CONTACT_ID1, yourNewRawContactId)
.withValue(AggregationExceptions.RAW_CONTACT_ID2, someExistingRawContactId)
.build());