我正在尝试使用以下函数将对象转换为URL编码字符串:
console.log(jQuery.param($scope.employee));
console.log($.param($scope.employee));
但他们给我一个错误:
TypeError:无法将对象转换为原始值 at encodeURIComponent() 在e(jquery-3.2.1.min.js:4) 在Ab(jquery-3.2.1.min.js:4) 在Function.r.param(jquery-3.2.1.min.js:4) at m。$ scope.save(employees.js:49) at fn(eval at compile(angular.min.js:241),:4:388) 在e(angular.min.js:286) at m。$ eval(angular.min.js:149) at m。$ apply(angular.min.js:150) 在HTMLButtonElement。 (angular.min.js:286)
$scope.employee
Data: Object
contact_number:"112"
created_at:"2017-08-08 05:27:03"
email:"asd@111.com"
id:9
name:"re"
position:"a"
updated_at:"2017-08-08 05:27:03"
这是使用在HomeStead上托管的Laravel和AngularJS开发的。 已安装Jquery。
更新仅用于验证目的:
模态HTML代码:
<div class="modal fade" id="myModal" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">×</span></button>
<h4 class="modal-title" id="myModalLabel">{{form_title}}</h4>
</div>
<div class="modal-body">
<form name="frmEmployees" class="form-horizontal" novalidate="">
<div class="form-group error">
<label for="inputEmail3" class="col-sm-3 control-label">Name</label>
<div class="col-sm-9">
<input type="text" class="form-control has-error" id="name" name="name" placeholder="Fullname" value="{{employee.data.name}}"
ng-model="employee.data.name" ng-required="true">
<span class="help-inline"
ng-show="frmEmployees.name.$invalid && frmEmployees.name.$touched">Name field is required</span>
</div>
</div>
<div class="form-group">
<label for="inputEmail3" class="col-sm-3 control-label">Email</label>
<div class="col-sm-9">
<input type="email" class="form-control" id="email" name="email" placeholder="Email Address" value="{{employee.data.email}}"
ng-model="employee.data.email" ng-required="true">
<span class="help-inline"
ng-show="frmEmployees.email.$invalid && frmEmployees.email.$touched">Valid Email field is required</span>
</div>
</div>
<div class="form-group">
<label for="inputEmail3" class="col-sm-3 control-label">Contact Number</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="contact_number" name="contact_number" placeholder="Contact Number" value="{{employee.data.contact_number}}"
ng-model="employee.data.contact_number" ng-required="true">
<span class="help-inline"
ng-show="frmEmployees.contact_number.$invalid && frmEmployees.contact_number.$touched">Contact number field is required</span>
</div>
</div>
<div class="form-group">
<label for="inputEmail3" class="col-sm-3 control-label">Position</label>
<div class="col-sm-9">
<input type="text" class="form-control" id="position" name="position" placeholder="Position" value="{{employee.data.position}}"
ng-model="employee.data.position" ng-required="true">
<span class="help-inline"
ng-show="frmEmployees.position.$invalid && frmEmployees.position.$touched">Position field is required</span>
</div>
</div>
</form>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-primary" id="btn-save" ng-click="save(modalstate, employee.data.id)" ng-disabled="frmEmployees.$invalid">Save changes</button>
</div>
</div>
</div>
</div>
注意:在本教程中,我关注ng-model
的值是:employee.position
但我将其更改为employee.data.position
,因为我将更新记录时的值未在字段中填充,但在添加data
后,现在已填充值。
我刚开始学习Laravel和AngularJS。
答案 0 :(得分:2)
如果您使用的是Angular,可以使用 $ httpParamSerializerJQLike ,示例代码:
.controller(function($http, $httpParamSerializerJQLike) {
//...
$http({
url: myUrl,
method: 'POST',
data: $httpParamSerializerJQLike(myData),
headers: {
'Content-Type': 'application/x-www-form-urlencoded'
}
});
});
答案 1 :(得分:1)
这可以在没有jQuery的情况下完成
var serialize = function(obj, prefix) {
var str = [], p;
for(p in obj) {
if (obj.hasOwnProperty(p)) {
var k = prefix ? prefix + "[" + p + "]" : p, v = obj[p];
str.push((v !== null && typeof v === "object") ?
serialize(v, k) :
encodeURIComponent(k) + "=" + encodeURIComponent(v));
}
}
return str.join("&");
}
使用console.log(serialize($scope.employee))