Question

我想编写一个以对象数组作为参数的函数。如果数组中的对象包含键＆＃34; name，＆＃34;我想将该密钥更改为＆＃34; title。＆＃34;然后我想返回更改了所有键的对象数组的更新版本。

这是我尝试这样做的。它没有按照我的意愿行事。

＆＃13;

execute

＆＃13;

以上代码返回：

const people = [{age: 32},{name: 'bob'},{name: 'jack', age: 3}];

function nameToTitle(arr){
  let result = [];
  for(let i = 0; i < arr.length; i++){
      if(arr[i].name){
        let newObj = {};
        for(let x in arr[i]){
          if(arr[i][x] === 'name'){
            newObj['title'] = arr[i][x];
          }
          else {
            newObj[x] = arr[i][x]; 
          }
        }
        result.push(newObj); 
      }  
      else {
        result.push(arr[i])
      }

  }
  return result;
}

console.log(nameToTitle(people));

它不会将名称密钥更改为＆＃34; title。＆＃34;

Answer 1

以下代码适用于您的用例。请注意，我已将people更改为可变变量（不再是const）。基本上所有这一切都是遍历数组中的每个字典，如果它找到一个带有"name"键的字典，它会设置一个具有相同值的"title"键，然后删除"name"键。

var people = [{age: 32}, {name: 'bob'}, {name: 'jack', age: 3}];

for (var i = 0; i < people.length; i++) {
  if (people[i].hasOwnProperty("name")) {
    people[i]["title"] = people[i]["name"];
    delete people[i]["name"];
  }
}

console.log(people);

Answer 2

你非常接近，你的if条件是检查对象的值而不是密钥。所以你需要做的就是改变：

if(arr[i][x] === 'name') // 'bob' === 'name' for {name: 'bob'}

为：

if(x === 'name') // 'name' === 'name' for {name: 'bob'}

因为x中for(let x in arr[i])的值是您要迭代的键值。

＆＃13;

const people = [{age: 32},{name: 'bob'},{name: 'jack', age: 3}];

function nameToTitle(arr){
  let result = [];
  for(let i = 0; i < arr.length; i++){
      if(arr[i].name){
        let newObj = {};
        for(let x in arr[i]){
          if(x === 'name'){
            newObj['title'] = arr[i][x];
          }
          else {
            newObj[x] = arr[i][x]; 
          }
        }
        result.push(newObj); 
      }  
      else {
        result.push(arr[i])
      }

  }
  return result;
}

console.log(nameToTitle(people));

＆＃13;

Answer 3

const people = [{age: 32},{name: 'bob'},{name: 'jack', age: 3}];

// Copy all properties.  If key is 'name' change it to 'title'
const copyObjectWithTitle = obj => 
  Object.keys(obj).reduce((objAcc, key) => {
    const value = obj[key];
    return Object.assign({}, objAcc, key === 'name' ? { title: value} : { [key]: value });
  }, {})

// Map over the list. If the object has the key 'name' return a copy with the key 'title' 
const nameToTitle = (list) => list.map(obj => obj.hasOwnProperty('name') ? copyObjectWithTitle(obj) : Object.assign({}, obj))

const updatedPeople = nameToTitle(people);

Answer 4

您可以映射数组中的对象并修改具有name属性的对象，如下所示

peoples.map(people => {
      if(people.hasOwnProperty('name')) {
        let title = people.name;
        delete people.name;
        return Object.assign({}, people, {title: title});
      }
      return people;
    })

Answer 5

如果您只想将name属性更改为title，我会这样做：

＆＃13;

function nameToTitle(objsArray){
  var s = objsArray.slice(), a; // make a copy
  for(var i in s){
    a = s[i];
    if(a.name){
      s[i].title = a.name; delete s[i].name;
    }
  }
  return s;
}
var objsArray = [{age:32},{name:'bob'},{name:'jack', age:3}];

console.log(nameToTitle(objsArray));

＆＃13;

Answer 6

这可能会有所下降，但只是为了好玩：]

const people = [{age: 32}, {name: 'bob'}, {name: 'jack', age: 3}];

const result = eval(JSON.stringify(people).replace(/\bname\b/g, 'title'));

console.log(result);

JavaScript - 满足条件时更改密钥

6 个答案: