使用python中的regex对单个长串字符串中的字符串进行分组

Question

所以我需要先根据段落之间的新行将整个字符串分组为块，然后将状态为Error的组块分组。 然后我需要使用正则表达式匹配动作，如果这些动作匹配，那么我需要将字符串（块的第一行）追加到列表中。 对python和regex来说很新，任何帮助都会受到关注。

"""

Some string that has some meaning.
Doing Action1 
Some error occurred which is logged
Reason for failures.
status: Error

Some other string that has some meaning
Doing Action2 
Some other error occurred which is logged
Reason for failures.
status: Error

Some new string that has some meaning
Doing Action1
Action was done
Reason for Action.
status: Ok

Some brand new string that has some meaning
Doing Action2
Action was done
Reason for Action.
status: Error
"""
The result expected should be something like this when checking for Action1
[Some string that has some meaning.]
when checking for Action2:
[Some other string that has some meaning,
 Some brand new string that has some meaning]

Answer 1

如果您尝试按当前格式的文本块进行分组，则应执行以下操作：

text_split = text.split('\n\n')

文本是你写的输出（？）

这应该给你一个块列表。 如果您想要在新列表中过滤掉包含status: Error的字符串块，您应该：

error_block = [x for x in text_split if 'status: Error' in x]