如何将从Twitter收到的数据存储到MongoDb中?

时间:2017-08-07 10:09:11

标签: java mongodb twitter4j

我从 twitter 检索数据并将其存储在List<>中。当尝试将其存储到 MongoDb 时,我收到错误信息。 " main"中的例外情况线程twitter4j.ResponseListImpl无法强制转换为com.mongodb.BasicDBObject

import java.net.UnknownHostException;
import java.util.List;
import com.mongodb.BasicDBObject;
import com.mongodb.DB;
import com.mongodb.DBCollection;
import com.mongodb.Mongo;
import com.mongodb.MongoException;

import twitter4j.ResponseList;
import twitter4j.Status;
import twitter4j.TwitterException;
import twitter4j.TwitterFactory;
import twitter4j.conf.ConfigurationBuilder;

public class SampleTwitter_data {
    public static void main(String[] args) throws TwitterException, UnknownHostException, MongoException {
    ConfigurationBuilder cofigurationBuilder =new ConfigurationBuilder();
    cofigurationBuilder.setDebugEnabled(true)
        .setOAuthConsumerKey("----------")
        .setOAuthConsumerSecret("----------")
        .setOAuthAccessToken("----------")
        .setOAuthAccessTokenSecret("----------");

     /**** Connect to MongoDB ****/
    Mongo mongo = new Mongo("localhost", 27017);


    /**** Get database ****/
    // if database doesn't exists, MongoDB will create it for you
    DB db = mongo.getDB("mydb");

    /**** Get collection / table from 'sample' ****/
    // if collection doesn't exists, MongoDB will create it for you
    DBCollection table = db.getCollection("sample");

    /**** Getting Data From Twitter time line ****/
    TwitterFactory tf = new TwitterFactory(cofigurationBuilder.build());
    twitter4j.Twitter twitter=tf.getInstance();
      ResponseList<Status> status= twitter.getHomeTimeline();
      for(Status s:status)
      {
          /**** here i'm getting error****/

          BasicDBObject document = new BasicDBObject();
          document=(BasicDBObject) status;
            table.insert(document);

            /**** just to make sure that i'm retrieving data from Twitter ****/
     System.out.println(s.getId()+s.getUser().getName()+"      "+s.getText());

      }
    }

}

1 个答案:

答案 0 :(得分:0)

来自Twitter4j的

Status不是Json,你应该先转换它。

cofigurationBuilder上,你必须设置JSONStorEnabled为真

        cb.setDebugEnabled(true).setOAuthConsumerKey(consumer_key")
                .setOAuthConsumerSecret("consumer_key_secret")
                .setOAuthAccessToken("access_token")
                .setOAuthAccessTokenSecret("access_token_secret")
                .setJSONStoreEnabled(true);

并且

 BasicDBObject document = new BasicDBObject();
 document=(BasicDBObject) status;

您需要从状态创建Json并使用mongo

解析它
                String json = TwitterObjectFactory.getRawJSON(status);
                DBObject dbObject = (DBObject) JSON.parse(json);
                collection.insert(dbObject);