Question

这是程序任何人都可以帮助我起初我给了字符串第一部分工作正常它在字符串中找到元音并打印

public static void main(String[] args) {
    // TODO Auto-generated method stub
    String a = "History can also refer to the academic discipline ";
    int count = 0;

    for (int i = 0; i < a.length(); i++) {  

        if (a.charAt(i) == 'a' || a.charAt(i) == 'e' || a.charAt(i) == 'i' || a.charAt(i) == 'u'
                || a.charAt(i) == 'u') {
            System.out.println("The sentence have vowels:" + a.charAt(i));
            count++;//counting the number of vowels
        }
        if (a.charAt(i+1) == 'a' || a.charAt(i+1) == 'e' || a.charAt(i+1) == 'i' || a.charAt(i+1) == 'u'
                || a.charAt(i+1) == 'u') {i++;}//finding reoccurring vowels 
    }
    System.out.println("number of vowels:" + count);
}

}

在第二部分我试图跳过重复发生的元音，但它不起作用

Answer 1

您需要进行一些更改：

运行循环直到a.length() - 1，因为您已经在循环中检查i+1个字符
如果不满足第二个if条件，则重置计数。

e.g：

public static void main(String[] args) {
    // TODO Auto-generated method stub
    String a = "History can also refer to the academic discipline ";
    int count = 0;

    for (int i = 0; i < a.length() - 1; i++) {  

        if (a.charAt(i) == 'a' || a.charAt(i) == 'e' || a.charAt(i) == 'i' || a.charAt(i) == 'u'
                || a.charAt(i) == 'u') {
            System.out.println("The sentence have vowels:" + a.charAt(i));
            count++;//counting the number of vowels
        }
        //finding reoccurring vowels
        if (a.charAt(i+1) == 'a' || a.charAt(i+1) == 'e' || a.charAt(i+1) == 'i' || a.charAt(i+1) == 'u'
                || a.charAt(i+1) == 'u') {
            i++;
         } else{
            count = 0;
         } 
    }
    System.out.println("number of vowels:" + count);
}

Answer 2

这个怎么样

    public static void main(String[] args) {
    String a = "History can also refer to the academic discipline ";
    int count = 0;

    boolean lastWasVowel = false;

    for (int i = 0; i < a.length(); i++) {

        if (a.charAt(i) == 'a' || a.charAt(i) == 'e' || a.charAt(i) == 'i' || a.charAt(i) == 'o'
                || a.charAt(i) == 'u') {
            if(!lastWasVowel) {
                count++;
            }
            lastWasVowel = true;
         } else {
            lastWasVowel = false;
        }
     }
    System.out.println("number of vowels:" + count);
}

删除字符串中的重复元音

2 个答案: