试图在c＃

Question

我试图通过在c＃console应用程序中运行该脚本来检索python脚本的控制台输出。但我不知道自己做错了什么，因为我无法阅读任何输出。请帮我。 这是我的代码示例：

Process proc = new Process();
try
{

    proc.StartInfo.FileName = "C:\\Program Files\\Python36\\python.exe";
    proc.StartInfo.Arguments = "\"E:/Database/Python Scripts/TestFile.py\" \"E:/Database/Testing.db\"";
    proc.StartInfo.UseShellExecute = false;

    proc.StartInfo.RedirectStandardOutput = true;
    proc.StartInfo.RedirectStandardError = true;
    proc.StartInfo.CreateNoWindow = true;
    proc.EnableRaisingEvents = true;

    proc.Start();

    while (!proc.StandardOutput.EndOfStream)
    {
        string line = proc.StandardOutput.ReadLine();
        Console.WriteLine("line:" + line);
    }

    Console.WriteLine("The End");

    Console.ReadLine();
}
catch(Exception ex)
{
    Console.WriteLine("Error:{0}, Detail: {1}", ex.Message, ex.StackTrace);

    Console.ReadLine();
}

finally
{
    //Console.ReadLine();
    proc.Close();
    proc.Dispose();
}

Answer 1

首先你需要设置proc.StartInfo.RedirectStandardOutput = false;为真 那么你需要监听输出事件

proc.StartInfo.FileName = "C:\\Program Files\\Python36\\python.exe";
proc.StartInfo.Arguments = "\"E:/Database/Python Scripts/TestFile.py\" \"E:/Database/Testing.db\"";
proc.StartInfo.UseShellExecute = false;

proc.StartInfo.RedirectStandardOutput = true;
proc.StartInfo.RedirectStandardError = true;
proc.StartInfo.CreateNoWindow = true;
proc.EnableRaisingEvents = true;
proc.OutputDataReceived+= ProcessOutputHandler;
proc.Start();
proc.BeginErrorReadLine();
proc.BeginOutputReadLine(); 

  private void ProcessOutputHandler(object sender, DataReceivedEventArgs e)
    {

        //get the data using e.Data

    }

您可以为ErrorOutput执行相同的操作，因为它们是您可以获得的单独流。要监听错误，只需为proc.ErrorDataReceived+= ProcessErrorOutputHandler;

添加一个事件监听器