我有一个很长的数组,我希望从中获取要显示的所有值 他们的php前端页面。我在数据库中有两个表。
列出商品 - pro_id,cat_id, cat_name,pro_name,price;
我的数组如下:
Array( [0] => Array (
[3] => Array( [cat_id] => 3
[cat_name] => Mobile Phones
[product] => Array(
[26] => Array(
[pro_id] => 26
[pro_name] => iPhone 7
[price] => 70000
)
[25] => Array(
[id] => 25
[pro_name] => iPhone 6
[price] => 60000
)
)
)
)
[1] => Array(
[5] => Array([id] => 5
[name] => Software
[product] => Array(
[21] => Array(
[id] => 21
[pro_name] => Lorem Ipsum is simply
[price] => 5000
)
[11] => Array
(
[id] => 11
[pro_name] => Lorem Ipsum is simply
[price] => 10000
)
)
)
)
[2] => Array( [4] => Array([id] => 4
[name] => Accessories
[product] => Array(
[20] => Array(
[id] => 20
[pro_name] => japan
[price] => 40000
)
)
)
)
我无法使用以下代码获取此数组的值:
if(!empty($product)){
foreach($product as $catname){
echo $catname['cat_name'];
echo "<br>";
foreach($product[] as $detail=> $row {
echo $row['product_id'];
echo $row['pro_name'];
echo $row['price'];
}
显示错误。但我想要这样的输出:
Mobile Phones
26
iPhone 7
70000
25
iPhone 6
60000
Software
21
Lorem Ipsum is simply
5000
11
Lorem Ipsum is simply
10000
Accessories
20
japan
40000
答案 0 :(得分:0)
简单,只能使用此功能:
function array_echo($array , $indent = 0)
{
foreach($array as $k=>$v)
{
echo "<br />";
for($i=0; $i<$indent; $i++)
echo "  ";
if(is_array($v))
{
echo "[$k] => ";
array_echo($v, ($indent+1));
}
else
echo "[$k] => [$v]";
}
}