无法访问视频流。任何人都可以帮助我获取视频流。我在谷歌搜索了解决方案并在堆栈溢出中发布了另一个问题,但遗憾的是没有什么不能解决问题。
import cv2
cap = cv2.VideoCapture()
cap.open('http://192.168.4.133:80/videostream.cgi?user=admin&pwd=admin')
while(cap.isOpened()):
ret, frame = cap.read()
cv2.imshow('frame', frame)
if cv2.waitKey(1) & 0xFF == ord('q'):
break
cap.release()
cv2.destroyAllWindows()
答案 0 :(得分:2)
您可以使用urllib从视频流中读取帧。
import cv2
import urllib
import numpy as np
stream = urllib.urlopen('http://192.168.100.128:5000/video_feed')
bytes = ''
while True:
bytes += stream.read(1024)
a = bytes.find(b'\xff\xd8')
b = bytes.find(b'\xff\xd9')
if a != -1 and b != -1:
jpg = bytes[a:b+2]
bytes = bytes[b+2:]
img = cv2.imdecode(np.fromstring(jpg, dtype=np.uint8), cv2.IMREAD_COLOR)
cv2.imshow('Video', img)
if cv2.waitKey(1) == 27:
exit(0)
如果您要从电脑的网络摄像头流式传输视频,请查看此信息。 https://github.com/shehzi-khan/video-streaming
答案 1 :(得分:2)
谢谢。可能是,现在urlopen不在utllib下。它位于urllib.request.urlopen下。我使用此代码:
import cv2
from urllib.request import urlopen
import numpy as np
stream = urlopen('http://192.168.4.133:80/video_feed')
bytes = ''
while True:
bytes += stream.read(1024)
a = bytes.find(b'\xff\xd8')
b = bytes.find(b'\xff\xd9')
if a != -1 and b != -1:
jpg = bytes[a:b+2]
bytes = bytes[b+2:]
img = cv2.imdecode(np.fromstring(jpg, dtype=np.uint8), cv2.IMREAD_COLOR)
cv2.imshow('Video', img)
if cv2.waitKey(1) == 27:
exit(0)
答案 2 :(得分:2)
您可以使用此代码在浏览器中获取实时视频供稿。
要访问笔记本电脑网络摄像头以外的摄像头,您可以使用RTSP链接
rtsp:// admin:12345@192.168.1.1:554 / h264 / ch1 / main / av_stream“
其中
username:admin password:12345 your camera ip address and port ch1 is first camera on that DVR
使用此链接为您的摄像机替换cv2.VideoCamera(0) 它会起作用
camera.py
import cv2
class VideoCamera(object):
def __init__(self):
# Using OpenCV to capture from device 0. If you have trouble capturing
# from a webcam, comment the line below out and use a video file
# instead.
self.video = cv2.VideoCapture(0)
# If you decide to use video.mp4, you must have this file in the folder
# as the main.py.
# self.video = cv2.VideoCapture('video.mp4')
def __del__(self):
self.video.release()
def get_frame(self):
success, image = self.video.read()
# We are using Motion JPEG, but OpenCV defaults to capture raw images,
# so we must encode it into JPEG in order to correctly display the
# video stream.
ret, jpeg = cv2.imencode('.jpg', image)
return jpeg.tobytes()
main.py
from flask import Flask, render_template, Response
from camera import VideoCamera
app = Flask(__name__)
@app.route('/')
def index():
return render_template('index.html')
def gen(camera):
while True:
frame = camera.get_frame()
yield (b'--frame\r\n'
b'Content-Type: image/jpeg\r\n\r\n' + frame + b'\r\n\r\n')
@app.route('/video_feed')
def video_feed():
return Response(gen(VideoCamera()),
mimetype='multipart/x-mixed-replace; boundary=frame')
if __name__ == '__main__':
app.run(host='0.0.0.0', debug=True)
然后您可以按照this blog来提高视频流的FPS
答案 3 :(得分:1)
您可以使用RTSP代替直接视频Feed。
每台IP摄像机都有RTSP来实时播放视频。
因此,您可以使用RTSP Link而不是视频输入
答案 4 :(得分:1)
使用以下代码直接通过opencv访问ipcam。用您的特定摄像机rtsp网址替换VideoCapture中的网址。给出的一个通常适用于我使用过的大多数相机。
import cv2
cap = cv2.VideoCapture("rtsp://[username]:[pass]@[ip address]/media/video1")
while True:
ret, image = cap.read()
cv2.imshow("Test", image)
if cv2.waitKey(1) & 0xFF == ord('q'):
break
cv2.destroyAllWindows()
答案 5 :(得分:-1)
如果使用python 3,则可能需要使用字节数组而不是字符串。 (修改当前的最佳答案)
with urllib.request.urlopen('http://192.168.100.128:5000/video_feed') as stream:
bytes = bytearray()
while True:
bytes += stream.read(1024)
a = bytes.find(b'\xff\xd8')
b = bytes.find(b'\xff\xd9')
if a != -1 and b != -1:
jpg = bytes[a:b+2]
bytes = bytes[b+2:]
img = cv2.imdecode(np.frombuffer(jpg, dtype=np.uint8), cv2.IMREAD_COLOR)
cv2.imshow('Video', img)
if cv2.waitKey(1) & 0xFF == ord('q'):
break
cv2.destroyAllWindows()