Question

如何在日期属性

中创建按日重组数组的函数

例如我有这个数组..

var _array = [ 
{name:"sample1" ,date:'08-07-2017'}, 
{name:"sample2" ,date:'08-07-2017'},
{name:"sample3" ,date:'08-08-2017'},
{name:"sample4" ,date:'08-09-2017'},
{name:"sample5" ,date:'08-09-2017'},
{name:"sample5" ,date:'08-09-2017'},
];

然后我调用函数regroup

regroup_byday(_array);

预期产出

{ 
   [
    {name:"sample1" ,date:'08-07-2017'}, 
    {name:"sample2" ,date:'08-07-2017'},
   ],

   [
   {name:"sample3" ,date:'08-08-2017'}, 
   ],

   [
    {name:"sample4" ,date:'08-09-2017'},
    {name:"sample5" ,date:'08-09-2017'},
    {name:"sample5" ,date:'08-09-2017'},
   ]
};

提前谢谢！ ..

Answer 1

以下内容应产生您正在寻找的所需输出：

var _array = [ 
{name:"sample1" ,date:'08-07-2017'}, 
{name:"sample2" ,date:'08-07-2017'},
{name:"sample3" ,date:'08-08-2017'},
{name:"sample4" ,date:'08-09-2017'},
{name:"sample5" ,date:'08-09-2017'},
{name:"sample5" ,date:'08-09-2017'},
];

var result = Object.values(
  _array.reduce((regroup, obj) => {
    if(regroup[obj.date] === undefined) {
      regroup[obj.date] = [obj];
    } else {
      regroup[obj.date].push(obj);
    }
    return regroup;
  }, {})
);

console.log(result);

Answer 2

循环遍历数组并将结果推送到中间的 Object ，并以日期为关键字， Object 的值将是您所需要的：

Capture<Class<?>>

按日期在数组中按日期属性重新组合

2 个答案: