Question

我有一个这样的自行车清单：

fmnewlist = [
    ['Bike No.', 'Purchase Date', 'Batt %', 'Last Maintenance', 'KM since Last', 'Reason/s'], 
    ['T101', '10/4/2016', '55', '10/1/2017', '25.08', 'No service'], 
    ['T102', '1/7/2016', '10', '15/5/2017', '30.94', 'No service'], 
    ['T103', '15/11/2016', '94', '13/6/2017', '83.16', 'KM'], 
    ['T104', '25/4/2017', '58', '10/1/2017', '25.08', 'No service'], 
    ['T105', '24/5/2017', '5', '20/6/2017', '93.8', 'Batt & KM']
]

我想检查每个内部列表中的某些元素，然后在没有循环的情况下打印出这样的字符串。这是我的代码，为什么它不起作用？

lens=len(fmnewlist)
biketocheck=(input("Bike No.:"))
countertwo=1

while countertwo < (lens+1):
    a=fmnewlist[countertwo]
    if biketocheck in a[0] and a[5]!="No service":
        print("Bike serviced.")
    elif biketocheck in a[0] and a[5]=="No service":
        print("Bicycle not due for servicing")
    elif biketocheck not in fmnewlist:
        print("No such bicycle")
    else:
        print(" ")
    countertwo+=1
    if countertwo==lens:
        break

输入T123时的预期输出：

Bike No.:T123
No such bicycle

实际输出：

Bike No.:T123
No such bicycle
No such bicycle
No such bicycle
No such bicycle
No such bicycle

输入为T102时的预期输出：

Bicycle not due for servicing

实际输出：

Bike No.:T102 No such bicycle Bicycle not due for servicing No such bicycle No such bicycle No such bicycle

输入为T103时的预期输出：

Bike serviced 实际输出：

Bike No.:T103 No such bicycle No such bicycle Bike serviced. No such bicycle No such bicycle

Answer 1

为什么不直接创建列表的查找地图并进行快速if .. in比较，例如：

fmnewlist = [
    ['Bike No.', 'Purchase Date', 'Batt %', 'Last Maintenance','KM since Last', 'Reason/s'], 
    ['T101', '10/4/2016', '55', '10/1/2017', '25.08', 'No service'], 
    ['T102', '1/7/2016', '10', '15/5/2017', '30.94', 'No service'], 
    ['T103', '15/11/2016', '94', '13/6/2017', '83.16', 'KM'], 
    ['T104', '25/4/2017', '58', '10/1/2017', '25.08', 'No service'], 
    ['T105', '24/5/2017', '5', '20/6/2017', '93.8', 'Batt & KM']
]

bike_iter = iter(fmnewlist)  # create an iterator for easier handling
next(bike_iter)  # skip the first item (header)
bike_nos = {bike[0]: bike[5] for bike in bike_iter}  # create bike_no: reason map

biketocheck = input("Bike No.: ")  # get the input

if biketocheck in bike_nos:  # check if the bike exists
    if bike_nos[biketocheck] == "No service":  # if it exists, check for status...
        print("Bicycle not due for servicing")
    else:
        print("Bike serviced.")
else:  # bike doesn't exist...
    print("No such bicycle")

如果你测试它：

Bike No.: T103
Bike serviced.

Bike No.: T102
Bicycle not due for servicing

Bike No.: T123
No such bicycle

Answer 2

我最好猜测该计划应该做什么：

查看第一个元素与用户指定ID匹配的行的自行车列表。
如果找不到自行车，请打印＆＃34;没有这样的自行车。＆＃34;
如果找到了自行车，请打印出＃34;自行车未到期服务＆＃34;或者＆＃34;自行车服务＆＃34;取决于第6个元素的值。

鉴于这些假设，我相信这段代码应该做你想要的：

fmnewlist = [
    ['Bike No.', 'Purchase Date', 'Batt %', 'Last Maintenance', 'KM since Last', 'Reason/s'], 
    ['T101', '10/4/2016', '55', '10/1/2017', '25.08', 'No service'], 
    ['T102', '1/7/2016', '10', '15/5/2017', '30.94', 'No service'], 
    ['T103', '15/11/2016', '94', '13/6/2017', '83.16', 'KM'], 
    ['T104', '25/4/2017', '58', '10/1/2017', '25.08', 'No service'], 
    ['T105', '24/5/2017', '5', '20/6/2017', '93.8', 'Batt & KM']
]

biketocheck=(input("Bike No.:"))

found = False
for bike in fmnewlist[1:]:
    if bike[0] == biketocheck:
        found = True

        if bike[5] == "No service":
            print("Bicycle not due for servicing")
        else:
            print("Bike serviced.")
        break

if not found:
    print("No such bicycle")

修改

使用dict代替，这使逻辑变得更容易：

bikes = { bike[0]:bike[1:] for bike in fmnewlist[1:] } biketocheck=(input("Bike No.:")) if biketocheck in bikes: if bikes[biketocheck][4] == "No service": print("Bicycle not due for servicing") else: print("Bike serviced.") else: print("No such bicycle")

Answer 3

使用for代替while，删除else部分。然后，您可以使用else语句for：

for bicycle in fmnewlist[1:]:  # Don't use the first line
    # previous statements except else, it should have a `break` too.
    if biketocheck in a[0]:
        if a[5]!="No service":
            print("Bike serviced.")
        # compare is either != or == so there's no need to write the whole elif 
        else:
            print("Bicycle not due for servicing")
        break
else:
    print("No such bicycle")

else仅在for完成且没有中断的情况下使用。所以这意味着没有找到自行车。你正在做的是检查每一行所需的自行车，当然它不存在于那个元素中。

P.S：您也可以将else与while一起使用。但是你必须确定条件在一段时间之后返回False，否则else子句将不起作用。 for执行此操作会更容易。

打印完某个字符串后的中断循环python

3 个答案: