$from = "2017-7-1";
$to = "2017-8-25";
我不知道为什么我似乎无法正确选择 HTML5日期选择器中的从日期,例如当我选择2017-7-1时,结果页面不会在2017-7-1上显示结果数据, 但是当我选择2017-6-30 一天之前时,它可以显示。 知道为什么吗? 我尝试了BETWEEN CLause和> = AND< =, 他们都不工作 知道为什么吗?感谢
$result = mysql_query("SELECT * FROM treatmentdetail WHERE nextdate BETWEEN
'$from' AND '$to'");
$result = mysql_query("SELECT * FROM treatmentdetail WHERE nextdate >=
'$from' AND nextdate <= '$to'");
答案 0 :(得分:1)
You should convert properly to date
SELECT *
FROM treatmentdetail
WHERE str_to_date(nextdate, '%Y-%m-%d')
BETWEEN str_to_date('$from','%Y-%m-%d' ) AND str_to_date('$to','%Y-%m-%d' )
and you should use most recent mysql driver .. with param binding too
答案 1 :(得分:0)
您缺少连接变量 我想你将不得不使用连接变量。
$result = mysqli_query($conn,"SELECT * FROM treatmentdetail WHERE nextdate BETWEEN
'$from' AND '$to'") or die(mysqli_error($conn));
答案 2 :(得分:0)
将您的字段更改为DATE和 将您的日期保存为YYYY-MM-DD,如您所示
$from = "2017-07-01";
$to = "2017-08-25";
您可以使用mysql(i)正确搜索
SELECT * FROM treatmentdetail
WHERE
nextdate >= '$from' AND nextdate <= '$to';
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