Question

我有5个实体，User，Roles，Permissions，UserRoles，PermisssionRoles，我如何使用数据透视表enter image description here构建一个JPA类来获取数据

public class Roles实现Serializable {

// @OneToMany（mappedBy =＆＃34; role_id＆＃34;） // private Collection permissionRoleCollection;

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Basic(optional = false)
@Column(name = "id")
private Integer id;
@Size(max = 100)
@Column(name = "name")
private String name;
@Size(max = 50)
@Column(name = "code")
private String code;
@Size(max = 255)
@Column(name = "brief")
private String brief;
@Size(max = 8)
@Column(name = "status")
private String status;
@Basic(optional = false)
@NotNull
@Column(name = "date_created")
@Temporal(TemporalType.TIMESTAMP)
private Date dateCreated;
@Column(name = "date_updated")
@Temporal(TemporalType.TIMESTAMP)
private Date dateUpdated;

@JoinColumn(name = "created_by", referencedColumnName = "id")
@ManyToOne
private User createdBy;
@JoinColumn(name = "updated_by", referencedColumnName = "id")
@ManyToOne
private User updatedBy;

@ManyToOne
@JoinTable(name = "permission_role",
        joinColumns = @JoinColumn(name = "userid",
                referencedColumnName = "userid"),
        inverseJoinColumns = @JoinColumn(name = "groupid",
                referencedColumnName = "groupid")
)
private Collection<PermissionRole> permissionRoles;

public Roles() {
}

public Roles(Integer id) {
    this.id = id;
}

public Roles(Integer id, Date dateCreated) {
    this.id = id;
    this.dateCreated = dateCreated;
}

public Integer getId() {
    return id;
}

public void setId(Integer id) {
    this.id = id;
}

public String getName() {
    return name;
}

public void setName(String name) {
    this.name = name;
}

public String getCode() {
    return code;
}

public void setCode(String code) {
    this.code = code;
}

public String getBrief() {
    return brief;
}

public void setBrief(String brief) {
    this.brief = brief;
}

public String getStatus() {
    return status;
}

public void setStatus(String status) {
    this.status = status;
}

public Date getDateCreated() {
    return dateCreated;
}

public void setDateCreated(Date dateCreated) {
    this.dateCreated = dateCreated;
}

public Date getDateUpdated() {
    return dateUpdated;
}

public void setDateUpdated(Date dateUpdated) {
    this.dateUpdated = dateUpdated;
}


public User getCreatedBy() {
    return createdBy;
}

public void setCreatedBy(User createdBy) {
    this.createdBy = createdBy;
}

public User getUpdatedBy() {
    return updatedBy;
}

public void setUpdatedBy(User updatedBy) {
    this.updatedBy = updatedBy;
}


@Override
public int hashCode() {
    int hash = 0;
    hash += (id != null ? id.hashCode() : 0);
    return hash;
}

@Override
public boolean equals(Object object) {
    // TODO: Warning - this method won't work in the case the id fields are not set
    if (!(object instanceof Roles)) {
        return false;
    }
    Roles other = (Roles) object;
    return !((this.id == null && other.id != null) || (this.id != null && !this.id.equals(other.id)));
}

@Override
public String toString() {
    return "myproperty.v1.db._entities.Roles[ id=" + id + " ]";
}

}

Answer 1

我想你希望在用户和角色之间以及角色和特权之间建立多对多的关系。如果你要声明@ManyToMany注释，hibernate会知道创建一个中间表...

Check this

你也可以通过编程方式创建＆＃34; inner＆＃34;表和注释从用户到内部的@OneToMany和从角色到内部的@OneToMany以及具有特权的相同

带透视表的高级JPA

1 个答案: