Question

在我的组件中，我解雇了我的行动：

 submitForm(e) {
  const language = e.target.value;
  this.props.actions.addLanguage(language, 'language', '2');
}

并连接到redux：

const mapStateToProps = state => ({
  UserDetails: state.UserDetails,
});

const mapDispatchToProps = dispatch => ({
  actions: bindActionCreators(UserActions, dispatch),
});

export default connect(mapStateToProps, mapDispatchToProps)(Screen1);

操作/索引：

import * as types from '../constants/ActionTypes';

export const addDetails = (age, gender, ethnicity) => ({
    type: types.ADD_DETAILS,
    age,
    gender,
    ethnicity,
});

export const addLanguage = (value, language, page) => ({
    type: types.ADD_LANGUAGE,
    value,
    language,
    page,
});

export const addAccessCode = (value, field) => ({
    type: types.ADD_ACCESSCODE,
    value,
    field,
});

的UserDetails：

import {
  ADD_DETAILS,
  ADD_ACCESSCODE,
  ADD_LANGUAGE,
  ADD_DRINKS,
} from '../constants/ActionTypes';

const initialState = {
  id: 0,
  language: '',
  session: '',
  values: '',
  accessCode: '',
  age: 0,
  gender: '',
  ethnicity: '',
  drinkOften: '',
  drinkConcern: '',
};

export default function UserDetails(state = initialState, action) {
  debugger;
  return (dispatch, state) => {
    switch (action.type) {
      case ADD_LANGUAGE:
        this.props.router.push(`${action.page}`);
        return {
          ...state,
          [action.field]: action.value,
        };

      case ADD_ACCESSCODE:
        return {
          ...state,
          [action.field]: action.value,
        };

      case ADD_DETAILS:
        return {
          ...state,
          ethnicity: action.ethnicity,
          gender: action.gender,
          age: action.age,
        };

      case ADD_DRINKS:
        return {
          ...state,
          [action.field]: action.value,
        };

      default:
        return state;
    }
  };
}

有什么想法吗？

@Ravindra Ranwala我可以用你的建议来解决这个问题，但是在减速器中它还没有定义，有什么想法吗？

使用我的调试器，操作实际上正在进行，但我的reducer无法通过thunk return (dispatch, getState) => {

Answer 1

将return语句添加到您的操作中。这将解决您的问题。就像这样。

export const toggleTodo = id => {
  return {
    type: 'TOGGLE_TODO',
    id
  }
}

希望这会有所帮助。快乐的编码！

Answer 2

删除fs/proc/array.c:do_task_stat()，您只需要在reducer中切换语句。以下是您的reducer应如何从redux文档中获取的示例。

＆＃13;

KSTK_EIP(task)

＆＃13;

减速器上的动作未定义

2 个答案: