Question

我成功运行了最长的单词函数，用于搜索数组中最长的单词：

var array = ["dog", "cat", "horse"];
var largest = 0;
var longestWord = " ";

for (var i = 0; i < array.length; i++) {
    if (array[i].length <= largest) {
    largest = array[i].length;
    longestWord = array[i];
    } 
}
console.log("The longest word is "+ longestWord);
console.log("The length of the word is " + largest);

试图有点聪明，我潜入并试图反转条件运算符以获得数组中的SHORTEST字：

var array2 = ["dog", "cat", "horse", "hsalsaaaaa"];
var shortest = 0;
var shortestWord = " ";

for (var i = 0; i < array2.length; i++) {
    if (array2[i].length < shortest) { // if an item length is less than 0 then
    shortest = array2[i].length; // shortest is equal to the length of the item
    shortestWord = array2[i]; // then " " will be the item itself;
    } 
}
console.log("The shortest word is "+ shortestWord);
console.log("The length of the word is " + shortest);

但是这段代码一直向我发送0和空白字。知道在这里调整一下吗？

谢谢！

Answer 1

您的代码失败的原因是因为没有小于" "的单词。

从

开始

var shortestWord = array2[0];

现在，从第一个元素开始迭代。

for (var i = 1; i < array2.length; i++) {
    ...
}

我更喜欢Infinity，因为您将迭代次数减少了1次。

＆＃13;

var array2 = ["dog", "cat", "horse", "hsalsaaaaa"];
var shortestWord = array2[0];

for (var i = 1; i < array2.length; i++) {
    if (array2[i].length < shortestWord.length) { // if an item length is less than 0 then
        shortestWord = array2[i]; // then " " will be the item itself;
    } 
}
console.log("The shortest word is "+ shortestWord);
console.log("The length of the word is " + shortestWord.length);

＆＃13;

我已经冒昧地删除shortest，因为它不是必需的。

Answer 2

您可以使用起始值而不是零Infinity，这是最大可能值。

var array2 = ["dog", "cat", "horse", "hsalsaaaaa"],
    shortest = Infinity,
    shortestWord,
    i

for (i = 0; i < array2.length; i++) {
    if (array2[i].length < shortest) { // if an item length is less than 0 then
        shortest = array2[i].length; // shortest is equal to the length of the item
        shortestWord = array2[i]; // then " " will be the item itself;
    }
}
console.log("The shortest word is " + shortestWord);
console.log("The length of the word is " + shortest);

Answer 3

您需要将初始化var shortest = 0;更新为var shortest = 100000;之类的内容。否则任何东西都不会小于0.这里100000表示任何非常大的值，并且单词的长度肯定不会那么大。

Answer 4

为什么要创建两个变量？ shortestWord就够了：

var arr = ["dog", "cat", "horse", "hsalsaaaaa"];
var shortestWord = arr[0]

for (var i = 0; i < arr.length; i++)
    if(arr[i].length < shortestWord.length) shortestWord = arr[i]; 

console.log("The shortest word is", shortestWord, ",length is", shortestWord.length);

Answer 5

var array2 = ["dog", "cat", "horse", "hsalsaaaaa"];
var shortest = 0;
var shortestWord = " ";

for (var i = 0; i < array2.length; i++) {
    if (array2[i].length <= shortest) { 
    shortest = array2[i].length; 
    shortestWord = array2[i];
    } 
}
console.log("The shortest word is "+ shortestWord);
console.log("The length of the word is " + shortest);

That was because your if condition was wrong

JavaScript中的创意短字

5 个答案: