Question

我有一张叫做员工的桌子：

CREATE TABLE Employees
(
   Id INT NOT NULL PRIMARY KEY IDENTITY(1,1),
   FullName NOT NULL NVARCHAR(100)
)

我有另一个名为Sales

的表

CREATE TABLE SALES 
(
   Id INT NOT NULL PRIMARY KEY IDENTITY(1,1),
   CustomerId INT NOT NULL FOREGIN KEY REFERENCES SOMETABLE(id),
   AMOUNT DECIMAL(15,4) NOT NULL,
   EmployeeId INT NOT NULL FOREGIN KEY REFERENCES Employees(Id),
   SaleDate DATETIME2 NOT NULL
)

另一个名为Calls的表

CREATE TABLE Calls
(
   Id INT NOT NULL PRIMARY KEY IDENTITY(1,1),
   Date DATETIME2 NOT NULL,
   EmployeeId INT NOT NULL FOREGIN KEY REFERENCES Employees(Id)
)

我需要运行一个查询，告诉我员工卖东西的最后日期，以及自那次销售以来他们怎么称呼他们。

我试过的是

SELECT
      LAST_DATE_SOLD = MAX(Sales.Date)
    , Employees.FullName
    , Count(Calls.*)
FROM Employees
LEFT OUTER JOIN SALES ON Sales.EmployeeId = Employees.Id
LEFT OUTER JOIN Calls On Calls.EmployeeId = Employees.Id
GROUP BY Employees.FullName

如果有人可以帮助解决这个问题，我没有得到正确的价值。

Answer 1

有很多方法可以给这只猫上皮。这是其中之一。请注意，这是加入呼叫，其中日期大于上次销售日期，因此它只返回这些呼叫。

with SortedResults as
(
    select *
        , ROW_NUMBER() over(partition by e.EmployeeID order by s.SalesDate desc) as RowNum
    from Sales s
    join Employee e on e.EmployeedID = s.Id
)

select s.SalesDate
    , s.FullName
    , count(*)
from SortedResults s
join Calls c on c.EmployeedId = s.EmployeeId and c.Date > s.SaleDate
where s.RowNum = 1
group by s.SalesDate, s.FullName

Answer 2

我认为Max(Sales.Date)不正确。试试这个

SELECT
      LAST_DATE_SOLD = MAX(SaleDate)
    , Employees.FullName
    , Count(Calls.*)
FROM Employees
LEFT OUTER JOIN SALES ON Sales.EmployeeId = Employees.Id
LEFT OUTER JOIN Calls On Calls.EmployeeId = Employees.Id
GROUP BY Employees.FullName

Answer 3

你可以试试这个：

WITH    qry1
      AS ( SELECT   EmployeeId ,
                    MAX(SaleDate) LatestSaleDate
           FROM     dbo.SALES
           GROUP BY EmployeeId
         )
SELECT  qry1.EmployeeId ,
        LatestSaleDate ,
        SUM(CASE WHEN c.date > LatestSaleDate THEN 1
                 ELSE 0
            END) NumberOfCalls
FROM    qry1
        LEFT JOIN Calls c ON qry1.EmployeeId = c.EmployeeId
GROUP BY qry1.EmployeeId, LatestSaleDate

Answer 4

SELECT e.fullname,
       c.date,
       COUNT(c.id)
  FROM calls c
 INNER JOIN employees e
    ON c.employee_id = e.employee_id
 WHERE date >= (SELECT MAX(saledate)
                  FROM sales
                 WHERE employee_id = c.employee_id
                )
 GROUP BY e.fullname,
          c.date

SQL Server Sum大于显示的日期

4 个答案: