Question

使用Bottle在python中开发Web应用程序。我想上传xlsx文件以从中加载数据。我使用openpyxl来做到这一点，但我得到一个错误

import wtforms
import openpyxl
from bottle import request, route, run, view,

我的表格：

class UploadForm(wtforms.Form):
    file = wtforms.FileField()

查看：

@route("/upload/file", method=['GET', 'POST'])
@view("upload")
def upload_file():
    form = UploadForm()
    if request.method == 'POST':
        form = UploadForm(request.POST)
        if form.validate():
            wb = openpyxl.load_workbook(form)
    return {'form': form}

模板：

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Title</title>
    <link rel="stylesheet" href="/static/css/normalize.css">
    <link rel="stylesheet" href="/static/css/skeleton.css">
</head>
<body>
    <form action="/upload/file" method="POST" enctype="multipart/form-data">
        {{ !form.file.label }}
        {{ !form.file }}
        <div class="row">
            <input type="submit" value="Upload" />
        </div>
    </form>
</body>
</html>

`错误：

Traceback (most recent call last):

    File "/home/wojjak/.local/lib/python2.7/site-packages/bottle.py", line 862, in _handle
return route.call(**args)
    File "/home/wojjak/.local/lib/python2.7/site-packages/bottle.py", line 1740, in wrapper
rv = callback(*a, **ka)
    File "/home/wojjak/.local/lib/python2.7/site-packages/bottle.py", line 3639, in wrapper
result = func(*args, **kwargs)
    File "/home/wojjak/PycharmProjects/untitled/parsowanie.py", line 84, in upload_file
if form.validate():
    File "/usr/local/lib/python2.7/dist-packages/openpyxl/reader/excel.py", line 171, in load_workbook
archive = _validate_archive(filename) 
    File "/usr/local/lib/python2.7/dist-packages/openpyxl/reader/excel.py", line 91, in _validate_archive
if not is_file_like and os.path.isfile(filename):  
    File "/usr/lib/python2.7/genericpath.py", line 37, in isfile
st = os.stat(path)
    TypeError: coercing to Unicode: need string or buffer, UploadForm found

任何人都知道如何解决这个问题

编辑：

确定。我解决了它

def upload_file():
form = UploadForm()
if request.method == 'POST':
    form = UploadForm(request.POST)
    if form.file.data:
        wb = openpyxl.load_workbook(request.files[form.file.name].file)

使用python wtforms openpyxl打开xlsx文件 - 错误

0 个答案: