我正面临一个问题。我目前正在创建一个运行任务的应用。某些任务可能会导致错误。在这种情况下，我在我的mongo db中存储我的任务状态。
我想创建一个加载每个错误任务并重新运行它们的作业。
查看数据结构：
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">Results</h4>
</div>
<div class="modal-body">
<div class="input-group input-group-md">
<span class="input-group-addon" id="sizing-addon1"><i class="fa fa-user" aria-hidden="true"></i></span>
<input type="text" class="form-control" id="contactModalPhoneInput" placeholder="Name" aria-describedby="basic-addon1" disabled/>
</div>
<br>
<button type="button" class="btn btn-danger pull-right" id="btnChangePhone">Change</button>
<br>
<div>
<h5>No Person Associated</h5>
<div>
<select id="dropdownPerson" title="Choose a Person"></select>
<div>
</div>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-danger" data-dismiss="modal" onclick="updatePerson()">Update</button>
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>
我想做的只是加载最后一个嵌入文档（而且只是最后一个）$('#dropdownPerson').multiselect();
for (let i = 0; i < 10; i++) {
let elem = document.createElement("option");
elem.textContent = i;
document.getElementById("dropdownPerson").appendChild(elem);
}
I am also adding the following to the html:
<!-- jQuery-->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script src="http://code.jquery.com/ui/1.10.2/jquery-ui.js"></script>
<!-- Bootstrap-->
<link href="../css/bootstrap.min.css" rel="stylesheet">
<link href="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" rel="stylesheet" type="text/css" />
<script type="text/javascript" src="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js"></script>
<!-- Multiselect-->
<link href="http://cdn.rawgit.com/davidstutz/bootstrap-multiselect/master/dist/css/bootstrap-multiselect.css" rel="stylesheet"
type="text/css" />
<script src="http://cdn.rawgit.com/davidstutz/bootstrap-multiselect/master/dist/js/bootstrap-multiselect.js" type="text/javascript"></script>
<!-- Imports-->
<script src="../js/globals.js"></script>
<script src="../js/utils.js"></script>
<script src="../js/functions.js"></script>
<script src="../js/populate.js"></script>
enter code here
到{
{
_id: 1,
actions: [
{
"name": "action_1",
"statuses": [
{
"date": "2017-08-04 15:37:54.000",
"status": "pending"
},
{
"date": "2017-08-04 15:37:56.000",
"status": "running"
},
{
"date": "2017-08-04 15:37:58.000",
"status": "passed"
}
]
}
]
},
{
_id: 2,
actions: [
{
"name": "action_1",
"statuses": [
{
"date": "2017-08-04 15:37:54.000",
"status": "pending"
},
{
"date": "2017-08-04 15:37:56.000",
"status": "running"
},
{
"date": "2017-08-04 15:37:58.000",
"status": "error"
}
]
}
]
},
{
_id: 3,
actions: [
{
"name": "action_1",
"statuses": [
{
"date": "2017-08-04 15:37:54.000",
"status": "pending"
},
{
"date": "2017-08-04 15:37:56.000",
"status": "error"
},
{
"date": "2017-08-04 15:37:56.000",
"status": "running"
},
{
"date": "2017-08-04 15:37:58.000",
"status": "passed"
}
]
}
]
},
{
_id: 4,
actions: [
{
"name": "action_1",
"statuses": [
{
"date": "2017-08-04 15:37:54.000",
"status": "pending"
},
{
"date": "2017-08-04 15:37:56.000",
"status": "error"
},
{
"date": "2017-08-04 15:37:56.000",
"status": "running"
},
{
"date": "2017-08-04 15:37:58.000",
"status": "passed"
}
]
},
{
"name": "action_2",
"statuses": [
{
"date": "2017-08-04 15:37:54.000",
"status": "pending"
},
{
"date": "2017-08-04 15:37:56.000",
"status": "error"
}
]
}
]
}
}
的文档。
最后，查询将返回包含ID actions.statuses.status和error的文档。
有没有办法说＆＃34;只有最后一个嵌入的文件＆＃34; ？
谢谢：）
答案 0 :(得分：1)
根据@NeilLunn解决方案，我将状态反向存储，以构建0位置的查询，如下所示：db.my_collection.find({"actions.0.statuses.0.status": "error"})
感谢他！