Question

我需要使用部分名称在目录中搜索文件。

前：

Directory : c:\Path
Filename  : Error_005296-895632-12563.xml
Partial file name: 005296-895632-12563

我在下面尝试过。

Directory.GetFiles("c:\Path", "*005296-895632-12563*.xml", SearchOption.AllDirectories).

但它没有工作

示例文件名是：

Error_005296-895632-12563.xml
005296-895632-12563_Response.xml
Duplicate_005296-895632-12563_Response.xml

Answer 1

您可以创建扩展方法并传递要查找的部分名称数组。

像这样调用扩展方法

DirectoryInfo dir = new DirectoryInfo(@"c:\demo");

FileInfo[] files = dir.GetFilesBypartialName("Anc_def_", "ABC_123", "12_qweqweqw_123").ToArray();

下面是扩展方法

public static class DirectoryFindFile
{
    public static IEnumerable<FileInfo> GetFilesBypartialName(this DirectoryInfo dirInfo, params string[] partialFilenames)
    {
        if (partialFilenames == null)
            throw new ArgumentNullException("partialFilenames");

        var lstpartialFilenames = new HashSet<string>(partialFilenames, StringComparer.OrdinalIgnoreCase);

        return dirInfo.EnumerateFiles()
            .Where(f => lstpartialFilenames.Contains(f.Name));
    }

    public static IEnumerable<FileInfo> GetFilesBypartialFilenamesAllDir(this DirectoryInfo dirInfo, params string[] partialFilenames)
    {
        if (partialFilenames == null)
            throw new ArgumentNullException("partialFilenames");

        var lstpartialFilenames = new HashSet<string>(partialFilenames, StringComparer.OrdinalIgnoreCase);

        return dirInfo.EnumerateFiles("*.*", SearchOption.AllDirectories)
                       .Where(f => lstpartialFilenames.Contains(f.Name));
    }
}

Answer 2

这是我用来搜索目录的扩展函数

public static IEnumerable<string> GetFiles(string path, string searchPatternExpression = "", SearchOption searchOption =    SearchOption.AllDirectories)
{

    Regex reSearchPattern = new Regex(searchPatternExpression);

    return Directory.EnumerateFiles(path, "*", searchOption).Where(file => reSearchPattern.IsMatch(System.IO.Path.GetExtension(file)));
 }

使用C＃中的部分名称在目录中搜索文件

2 个答案: