Question

如何在laravel 5.4中运行此类查询

     select items.id,items.name,total,region from items LEFT OUTER JOIN
     (select  purchases.region_id as region , sum(purchases_detail.quantity) 
     as total,purchases_detail.item_id
     from purchases_detail
     left join purchases on(purchases.id=purchases_detail.purchase_id)
     GROUP BY purchases_detail.item_id) pd on (pd.item_id=items.id)

当我在DB :: select（''）中尝试这个时它给了我一个错误：

SQLSTATE [42000]：语法错误或访问冲突：1055'amsdb.purchases.region_id'不在GROUP BY中（SQL：select items.id，items.name，total，items from LEFT OUTER JOIN （选择purchases.region_id作为区域，sum（purchases_detail.quantity）为total，purchases_detail.item_id 来自purchases_detail 离开加入购买（purchases.id = purchases_detail.purchase_id） GROUP BY purchases_detail.item_id）pd on（pd.item_id = items.id））

但是当我运行Phpmyadmin

时效果很好

Answer 1

正如错误消息所示，purchases.region_id列不会显示为聚合，也不会按其进行分组。快速解决方法是从内部和外部查询中删除此列：

SELECT
    items.id,
    items.name,
    pd.total
FROM items
LEFT JOIN
(
    SELECT
        t1.item_id,
        SUM(t1.quantity) AS total
     FROM purchases_detail t1
     LEFT JOIN purchases t2
         ON t2.id = t1.purchase_id
     GROUP BY t1.item_id
) pd
     ON pd.item_id = items.id

Answer 2

Not sure, but I think that the select() method cannot contain all your SQL query.

I don't know if it will work, but try this one. It uses many query builder functions:

$subQuery = DB::table('purchases_detail')
    ->select(DB::raw('purchases.region_id as region , sum(purchases_detail.quantity) 
     as total,purchases_detail.item_id'))
    ->leftJoin('purchases', 'purchases.id', '=', 'purchases_detail.purchase_id')
    ->groupBy('purchases_detail.item_id')
    ->toSql();

$result = DB::table('items')
    ->select('items.id', 'items.name', 'total,region')
    ->leftJoin($subQuery . ' pd', 'pd.item_id', '=', 'items.id') // if not working, try ->leftJoin(DB::raw($subQuery) . ' pd', 'pd.item_id', '=', 'items.id')
    ->get();

Since your query has a nested SELECT, you have to make it in two times.

laravel 5中的自定义查询

2 个答案: