Question

我有以下代码行。我想在info中获取堆栈名称（标记为stack）。我还在学习阶段。我只想要前2个循环（for和if）并且在info我需要一个单独的循环，我循环通过其值在列表中的字典。我将这些值与volume id（我从1st volume.id循环获得的for）进行比较，当我得到匹配时，我将该字典的键放到stack。我尝试的是下面但这是不对的，因为我没有必要循环，我从第一个循环得到重复卷的长列表。
任何人都可以让我知道如何在stack下的一行中循环遍历字典列表值的元素？如果我需要提供更多信息，请告诉我。

for volume in volumes:
        if volume.snapshot_id == snapshot_id:
            for key,value in tempDict.items():
                for elem in value:
                    if volume.id == elem:
                       stack = key
                       info={'type':'volume',
                             'id':volume.id,
                             'display_name':volume.display_name,
                             'snapshot_id':volume.snapshot_id,
                             'created_at':volume.created_at,
                             'snapshots':[], 
                             'stack': stack}# This is where I need to work
                       vol_list.append(info)}

我在下面尝试stack，但我还需要添加if volume.id == elem，如果匹配则key进入stack

stack: {k:[elem for elem in v] for k,v in tempDict.iteritems()}}

我的字典如下所示

{
    "deployCI2": [
        "094fd196-20f0-4e8d-b946-f74a56d2f319",
        "6a1ce382-98c6-4058-a929-95a7d2415fd0",
        "156a1409-c89d-48fe-af6a-cad12d985b7a",
        "7376f485-6f70-4e35-a16e-b3136523206b"
    ],
    "deployCI3": [
        "c8fff661-4482-4908-b722-4fac0227a8b0",
        "929cf1fa-3fa6-4f95-8464-d58e5490f4cf",
        "4c7a7755-8576-43d0-9e7a-ae7319f40f6d",
        "a8460ed5-913b-4670-a1d4-43af508c8187"
    ],
    "Lomka": [
        "17efb1f1-3bf2-44f0-97a1-ebca4b6a2a30"
    ],
    "HeenaStackXYZ": [],
    "deployCI4": [
        "9f8ffa3c-460d-43a9-8113-58e891340e1b",
        "6e535e92-4da2-4228-a6ab-c8fc8d31adcd",
        "8e26a35e-7fb9-43b3-8026-d1283f7b678c",
        "f40e5c29-b4df-4cfb-9d7f-3bcc9c4dcf9f"
    ],
    "HeenaStackXYZ-VM1-ne4rpss4bnft": [],
    "ci_a3077f8b": [
        "0956d6a3-87f4-43c3-a2f7-8a963b2d00c3"
    ]
}

输出应该是什么样的？实际上这将是HTML。我主要担心的是获取堆栈名称。我做了什么

1. Fetch the stack names and the ID of the volumes associated with the stack. You see that in my dictionary. 
2. I compare all the volumes in my environment and see if any volume id matches with the stack's volume ID. If yes, I need to grab that stack name and put that in the info section (That's where stack comes)

Answer 1

I tried reversing the dictionary and for the stack I added - 'stack':{value for key, value in reversedDict.items() if volume.id == key}} This worked for me.

如何在一行中获取列表字典

1 个答案: