我想帮助我的表格。目前,当用户提交表单时,表单会自行提交(进入main.php)。我想在提交之前进行预检查,看看表格是否已完全填写。
以下是表单的HTML:
<div id="reqForm" class="modal">
<div class="modal-content">
<div class="modal-header">
<span class="close">×</span>
<h2>Reimbersement Form</h2>
</div>
<div class="modal-body">
<div class="form">
<h2>Enter your information:</h2>
<br/>
<h3>
<form action="main" method="post" id="newRequest">
<label>Full Name:</label> <input type="text" name="name" value="<?php echo $name; ?>" disabled/><br />
<label>Reimberse Amount:</label> <input type="number" min="0" name="amount" /><br />
Customer Name: <select name="customerName" id="cN"><option value="" id='cPlSe' selected>--Select--</option><?php
echo $optionC;
?></select><br />Project Name: <select name="projectName" id="pN"><option value="" id='plSe' selected>Please select customer name </option><option value="">--Select--</option><?php
echo $optionP;
?></select><br />
<label>Reason (max length 255 characters): </label><br /><textarea cols="40" rows="1" form="newRequest" name="reason"></textarea><br />
<input type="hidden" name="submitted"/>
</h3>
</div>
</div>
<div class="modal-footer"><br />
<input type="submit" id="submit"/>
</form>
</div>
</div>
</div>
和我的PHP:
if(isset($_POST["submitted"])){
$name = $_SESSION["name"];
$amount = $_POST["amount"];
$projectName = $_POST["projectName"];
$customerName = $_POST["customerName"];
$reason = $_POST["reason"];
$d = array("name"=>$name,"amount"=>$amount,"projectName"=>$projectName,"customerName"=>$customerName,"reason"=>$reason);
foreach($d as $i) {
if("" == trim($i)) {
echo "Make sure you have filled out all the fields. Click <a href='main'>here</a> to go back.";
exit();
}
}
foreach($d as $i) {
mysqli_real_escape_string($connect, $i);
}
$name = $d["name"];
$amount = $d["amount"];
$projectName = $d["projectName"];
$customerName = $d["customerName"];
$reason = $d["reason"];
$query = "INSERT INTO `requests` (`Name`, `Amount`, `ProjectName`, `CustomerName`, `Reason`) VALUES " . "('" . $name . "', '" . $amount . "', '" . $projectName . "', '" . $customerName . "', '" . $reason."');";
if (mysqli_query($connect, $query)) {
echo "Success!";
} else {
echo "Error: " . $query . "<br>" . mysqli_error($connect);
}
}
注意:我正在使用https://www.w3schools.com/howto/howto_css_modals.asp
中显示的表单模式答案 0 :(得分:1)
<input required></input>
您可以使用输入标记的“必需”attr
答案 1 :(得分:1)
如果您可以使用第三方库,我建议您使用parsleyJs。有了它,你可以使用
$('form').parsley().validate()
检查表格是否有效。
如果您想检查所有内容是否已填满,您需要使用required
标记,还可以使用其他类型和标记
https://www.w3schools.com/html/html_form_input_types.asp