Question

我的代码正在尝试组装给定大小的可视棋盘，然后将其输出到console.log。基本上，它：

循环遍历董事会中的所有行
循环遍历行中的所有列
如果列位置是偶数行，则会放置一个空格
如果列位置是奇数行，则会放置一个黑色空格。

我的代码：

＆＃13;

var sz = Number(prompt("What size chessboard?"))
console.log("Board of size " + sz + " selected.") 
var row = 0
var rowType = "even"
var col = 0
var bd = ""
var whiteSpace = "[]"
var blackSpace = "()"

for (row; row <= sz; row++) {
  if (row % 2 == 0) {rowType = "even";}  // For even rows, all even column places are white
  else {rowType = "odd";}  // and for odd rows, all even column places are black
  for (col = 0; col <= sz; col++) {
    if (col % 2 == 0) {
      if (rowType == "even") {bd += whiteSpace;}
      if (rowType == "odd") {bd += blackSpace;}
      else {console.log("Something went terribly wrong.")}  // This should never happen... right?
    }
    else {
      if (rowType == "even") {bd += blackSpace;}
      if (rowType == "odd") {bd += whiteSpace;}
      else {console.log("Something went horribly wrong.")}  // Not this one either?
    }
  }
  bd += "\n"
}
console.log(bd)

＆＃13;

出于某种原因，我提出的额外代码只是为了捕捉if {02}}的情况，而不是＆＃34;甚至＆＃34;或＆＃34;奇数＆＃34;似乎总是执行，把...＆34;某些事情变得非常/非常错误＆＃34;在rowType，即使代码工作正常，董事会实际上是正确生产的。

我的问题不是如何摆脱这些界限，显然我可以删除console.log块，但我很好奇我的错误在哪里使它成为现实跑在第一位。

有什么想法吗？

Answer 1

如你所愿，你正在做：

if (rowType == "even") {bd += whiteSpace;}
if (rowType == "odd") {bd += blackSpace;}
else {console.log("Something went terribly wrong.")} // <- will execute if
                                                     //    not 'odd'

应该是：

if (rowType == "even") {bd += whiteSpace;}
else if (rowType == "odd") {bd += blackSpace;}
else {console.log("Something went terribly wrong.")} // <- will execute if
                                                     //    not 'even' or 'odd'

Javascript - if和else语句都在执行

1 个答案: