Question

我是jquery的新手。我按照link来学习滑动右侧功能。我试图在我的项目中应用滑动右侧功能。但是，当我向右滑动时，它没有任何响应。我想在我在此页面的任何位置向右滑动时触发向右滑动功能。我不知道哪个部分出了问题。这是我的代码。

<!DOCTYPE html>
<html lang="en-US">
<head>
    <title>Tinder-like Marketplace - Mobile Shop Template</title>
    <meta charset="utf-8">
    <meta content="IE=edge" http-equiv="x-ua-compatible">
    <meta content="initial-scale=1.0, maximum-scale=1.0, minimum-scale=1.0, user-scalable=no" name="viewport">
    <meta content="yes" name="apple-mobile-web-app-capable">
    <meta content="yes" name="apple-touch-fullscreen">

    <link rel="stylesheet" type="text/css" href="css/style.css">
    <link rel="stylesheet" type="text/css" href="css/responsive.css">
    <link rel="shortcut icon" href="images/favicon.png">
    <link rel="stylesheet" href="https://code.jquery.com/mobile/1.4.5/jquery.mobile-1.4.5.min.css">
    <script src="https://code.jquery.com/jquery-1.11.3.min.js"></script>
    <script src="https://code.jquery.com/mobile/1.4.5/jquery.mobile-1.4.5.min.js"></script>
    <script>
$("body").on("swiperight",function(){
  alert("swipe right");
});
</script>
</head>

<body onload="initSwipe()">

<div id="main">

    <!-- MAIN PAGE -->
    <div id="page">


        <!-- CONTENT CONTAINER -->
        <div class="content-container">

            <!-- Product Header -->
            <div class="content-header">

                <div class="product-title animated fadeIn" id="productName">

                </div><!-- Product title -->

                <img src="images/240x240.png" alt="img" />

                <!-- Product meta -->
                <div class="product-meta animated fadeInUp">
                    <div class="product-title animated fadeIn">$</div>
                    <div class="product-title animated fadeIn" id="productPrice">

                    </div>
                 </div>      
</div>
         <div class="line"></div>


        </div>
        <!-- END CONTENT CONTAINER -->


        <div id="swipeLike" class="main-bg"><i class="fa fa-plus"></i></div>
        <div id="swipeUnlike" class="main-bg"><i class="fa fa-plus"></i>
     </div>

    </div>


</div>

<script type="text/javascript" src="js/jquery-3.1.1.js"></script>
<script type="text/javascript" src="js/materialize.min.js"></script>
<script type="text/javascript" src="js/slick.min.js"></script>
<script type="text/javascript" src="js/jquery.slicknav.js"></script>
<script type="text/javascript" src="js/jquery.swipebox.js"></script>
<script type="text/javascript" src="js/custom.js"></script>
<script type="text/javascript" src="js/swipe.js"></script>


</body>
</html>

Answer 1

尝试 100％正常工作：

定义swiperight和swipeleft或使用此代码：

$(document).on('swipeleft', 'body', function(event){ });
$(document).on('swiperight', 'body', function(event){ });

示例：

＆＃13;
＆＃13;
$(document).on('swipeleft', 'body', function(event){ alert("swipeleft"); return false; }); $(document).on('swiperight', 'body', function(event){ alert("swiperight"); return false; });
＆＃13;
<!DOCTYPE html> <html> <head> <title>Swiperight Example</title> <meta name="viewport" content="width=device-width,height=device-height,minimum-scale=1,maximum-scale=1"/> <link rel="stylesheet" href="//code.jquery.com/mobile/1.4.2/jquery.mobile-1.4.2.min.css" /> <script src="//code.jquery.com/jquery-1.10.1.min.js"></script> <script src="//code.jquery.com/mobile/1.4.2/jquery.mobile-1.4.2.min.js"></script> </head> <body> <p>Try to Swipe Right or Left</p> </body> </html>
＆＃13;
＆＃13;
＆＃13;

swiperight功能不起作用

1 个答案: