Question

基于此数组json我需要不断合并它。使用push（）我得到了这种结果

JSON
**0:**{
    "net_drops.vpn0": {
        "name":"net_drops.vpn0",
        "context":"net.drops",
        "units":"drops/s",
        "last_updated": 1501806176,
        "dimensions": {
            "inbound": {
                "name": "inbound",
                "value": 0.0000000
            },
            "outbound": {
                "name": "outbound",
                "value": 0.0000000
            }
        }
    },
    "named_local.view_resolver_numfetch__default": {
        "name":"named_local.view_resolver_numfetch__default",
        "context":"named.resolver_active_queries",
        "units":"queries",
        "last_updated": 1501806176,
        "dimensions": {
            "queries": {
                "name": "queries",
                "value": 0.0000000
            }
        }
    }

}
**1:**{
    "net_drops.vpn0": {
        "name":"net_drops.vpn0",
        "context":"net.drops",
        "units":"drops/s",
        "last_updated": 1501806176,
        "dimensions": {
            "inbound": {
                "name": "inbound",
                "value": 0.0000000
            },
            "outbound": {
                "name": "outbound",
                "value": 0.0000000
            }
        }
    },
    "named_local.view_resolver_numfetch__default": {
        "name":"named_local.view_resolver_numfetch__default",
        "context":"named.resolver_active_queries",
        "units":"queries",
        "last_updated": 1501806176,
        "dimensions": {
            "queries": {
                "name": "queries",
                "value": 0.0000000
            }
        }
    }

}
...

但我需要这种结果

JSON
{
    "net_drops.vpn0": {
        **0:**{"name":"net_drops.vpn0",
        "context":"net.drops",
        "units":"drops/s",
        "last_updated": 1501806176,
        "dimensions": {
            "inbound": {
                "name": "inbound",
                "value": 0.0000000
            },
            "outbound": {
                "name": "outbound",
                "value": 0.0000000
            }
        }},
        **1:**{"name":"net_drops.vpn0",
        "context":"net.drops",
        "units":"drops/s",
        "last_updated": 1501806176,
        "dimensions": {
            "inbound": {
                "name": "inbound",
                "value": 0.0000000
            },
            "outbound": {
                "name": "outbound",
                "value": 0.0000000
            }
        }}      
    },
    "named_local.view_resolver_numfetch__default": {
        **0:**{"name":"named_local.view_resolver_numfetch__default",
        "context":"named.resolver_active_queries",
        "units":"queries",
        "last_updated": 1501806176,
        "dimensions": {
            "queries": {
                "name": "queries",
                "value": 0.0000000
            }
        }},
        **1:**{"name":"named_local.view_resolver_numfetch__default",
        "context":"named.resolver_active_queries",
        "units":"queries",
        "last_updated": 1501806176,
        "dimensions": {
            "queries": {
                "name": "queries",
                "value": 0.0000000
            }
        }}      
    }
    ...
}

有可能吗？如果是，我该怎么办？

然后我需要根据last_update切片对象，如果last_update超过当前时间的30分钟被切片例如：当前时间10：00：00，对象last_update 09:31:00被切片。可能吗？如果是，我该怎么办？最好的问候

Answer 1

看起来您正在使用相同的密钥组合数据。

要实现该结果，请循环访问原始JSON数据并按键将其推送到另一个数组。在您的情况下，密钥是：＆＃39; net_drops.vpn0＆＃39;和＆＃39; named_local.view_resolver_numfetch__default＆＃39;喜欢：array.net_drops.vpn0 = json_data

对于基于＆＃39; last_updated＆＃39;的切片键，您可以尝试使用array.filter功能。请查看此LINK以供参考。

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1 个答案: