Question

我正在使用SQL2012。我有以下SQL表，显示案例编号及其值。案例编号总是出现3个案例。你能帮我转动桌子吗？案件数量超过一千。

case  value
A     1992
A     1956
A     2007
B     2000
B     2001
B     1990
C     2000
C     1956
C     1817

预期结果：

Case  value1   value2   value3
A    1992      1956     2007
B    2000      2001     1990
C    2000      1956     1817

Answer 1

使用ROW_NUMBER并应用条件聚合：

WITH Cte AS(
    SELECT *,
        Rn = ROW_NUMBER() OVER(PARTITION BY [case] ORDER BY (SELECT NULL))
    FROM Tbl
)
SELECT
    [case],
    value1 = MAX(CASE WHEN Rn = 1 THEN value END),
    value2 = MAX(CASE WHEN Rn = 2 THEN value END),
    value3 = MAX(CASE WHEN Rn = 3 THEN value END)
FROM Cte
GROUP BY [case];

ONLINE DEMO

Answer 2

我会将此问题作为对您之前的问题的跟进来解决，您需要计算无论顺序如何共享相同值的案例的频率。 Previous question

declare  @Table1 TABLE
    ([case] varchar(1), [value] int)
;

INSERT INTO @Table1
    ([case], [value])
VALUES
    ('A', 1992),    ('A', 1956),    ('A', 1986),
    ('B', 2000),    ('B', 2001),    ('B', 2003),
    ('C', 1986),    ('C', 1956),    ('C', 1992),
    ('D', 2005),    ('D', 2008),    ('D', 2002),
    ('E', 1954),    ('E', 1956),    ('E', 1992),
    ('G', 1954),    ('G', 1992) ,   ('G', 1956)


select min([case]) 'Case', min, mid, max,  count (*) frequency
from (
  select a.[case] [case], min(a.value) min, max(a.value) max, 
         sum(a.value)-min(a.value)-max(a.value) mid
  from @Table1 a      
  group by a.[case]) b
 group by min, mid, max
 order by min([case])

结果：

Case    min     mid     max     frequency
A       1956    1986    1992    2
B       2000    2001    2003    1
D       2002    2005    2008    1
E       1954    1956    1992    2

修改如果您只需要4列没有频率，这就足够了：

select a.[case] [Case], min(a.value) Value1, sum(a.value)-min(a.value)-max(a.value) Value2, max(a.value) Value3 from @Table1 a group by a.[case]

结果：

Case Value1 Value2 Value3 A 1956 1986 1992 B 2000 2001 2003 C 1956 1986 1992 D 2002 2005 2008 E 1954 1956 1992 G 1954 1956 1992

SQL Pivot表以3行为一组

2 个答案: