如何在scala play 2.6中的ActionBuilder中设置会话?

时间:2017-08-03 23:33:24

标签: scala session playframework actionbuilder

documentation on ActionBuilder包含三个节点的管道:身份验证,添加信息,验证步骤。

我想在身份验证步骤中设置会话值。我的意思是来自.withSession

Ok(_).withSession(_)
import play.api.mvc._

class UserRequest[A](val username: Option[String], request: Request[A]) extends WrappedRequest[A](request)

class UserAction @Inject()(val parser: BodyParsers.Default)(implicit val executionContext: ExecutionContext)
    extends ActionBuilder[UserRequest, AnyContent] with ActionTransformer[Request, UserRequest] {
    def transform[A](request: Request[A]) = Future.successful {
        new UserRequest(request.session.get("username"), request)
    }
}

1 个答案:

答案 0 :(得分:1)

您需要执行操作合成以将值添加到请求会话中,如下所示:

object WithSession extends ActionBuilder[Request] {
  def invokeBlock[A](request: Request[A], block: (Request[A]) => Future[Result]) = {
      block(request).map(_.withSession("key" -> "value"))
  }
}

在您的控制器中:

def index = WithSession {
  Ok("result")
}