您好我正在尝试打印" temp"变量所以我使用print(temp)
def delete_first(self):
if self.head:
deleted_element = self.head
temp = deleted_element.next
print(temp)
self.head = temp
return deleted_element
else:
return None
为什么我会得到这样的输出?这是内存中的对象地址吗?我修复它,以便打印出更有意义/可读的对象名称?
<__main__.Element object at 0x10071d5d0>
完整代码:
class Element(object):
def __init__(self, value):
self.value = value
self.next = None
class LinkedList(object):
def __init__(self, head=None):
self.head = head
def append(self, new_element):
current = self.head
if self.head:
while current.next:
current = current.next
current.next = new_element
else:
self.head = new_element
def insert_first(self, new_element):
new_element.next = self.head
self.head = new_element
def delete_first(self):
if self.head:
deleted_element = self.head
temp = deleted_element.next
print(temp)
self.head = temp
return deleted_element
else:
return None
class Stack(object):
def __init__(self, top=None):
self.ll = LinkedList(top)
def push(self, new_element):
self.ll.insert_first(new_element)
def pop(self):
return self.ll.delete_first()
# Test cases
# Set up some Elements
e1 = Element(1)
e2 = Element(2)
e3 = Element(3)
e4 = Element(4)
# Start setting up a Stack
stack = Stack(e1)
# Test stack functionality
stack.push(e2)
stack.push(e3)
print stack.pop().value
print stack.pop().value
print stack.pop().value
print stack.pop()
stack.push(e4)
print stack.pop().value
完整输出:
&lt; main .Element对象位于0x10071d5d0&gt; 3 &lt; main .Element对象位于0x10071d590&gt; 2 没有 1 没有 没有 4
答案 0 :(得分:-1)
您需要为此类定义__str__
方法(当然,如果您拥有它),例如Java中的toString()
。
例如:
class Element():
attr_1 = 0
attr_2 = 0
def __str__(self):
return '%s, %s' % (self.attr_1, self.attr_2)