我正在构建一个flashcard应用程序。我在下面附上了我的代码。当下面的代码运行时,用户应该能够向左和向右滑动一系列卡片(每张卡片包含一个与声音相结合的图像。有两个名为firstList和secondList的卡片阵列)。轻触图像时,应该播放与之耦合的声音。我没有在播放声音或刷一个列表时遇到问题。但是,当我尝试组合并滑动" firstList"时,我收到错误。和" secondList"。我似乎无法弄清楚的一个错误是"表达式的类型是不明确的,没有更多的上下文"。请参阅下面的代码和错误
import UIKit
class SecondViewController: UIViewController , UIGestureRecognizerDelegate {
var imageIndex: Int = 0
@IBAction func home(_ sender: Any) {
performSegue(withIdentifier: "home", sender: self)
}
@IBOutlet weak var imgPhoto: UIImageView!
struct List {
let words: [Card] /*Create array of cards*/
var active: Bool
}
let firstList = [
Card(image: UIImage(named: "lake")!, soundUrl: "Lake"),
Card(image: UIImage(named: "lamb")!, soundUrl: "Lamb"),
Card(image: UIImage(named: "lamp")!, soundUrl: "Lamp"),
Card(image: UIImage(named: "lark")!, soundUrl: "Lark"),
Card(image: UIImage(named: "leaf")!, soundUrl: "Leaf"),
Card(image: UIImage(named: "leash")!, soundUrl: "Leash"),
Card(image: UIImage(named: "left")!, soundUrl: "Left"),
Card(image: UIImage(named: "leg")!, soundUrl: "Leg"),
Card(image: UIImage(named: "lime")!, soundUrl: "Lime"),
Card(image: UIImage(named: "lion")!, soundUrl: "Lion"),
Card(image: UIImage(named: "lips")!, soundUrl: "Lips"),
Card(image: UIImage(named: "list")!, soundUrl: "List"),
Card(image: UIImage(named: "lock")!, soundUrl: "Lock"),
Card(image: UIImage(named: "log")!, soundUrl: "Log"),
Card(image: UIImage(named: "look")!, soundUrl: "Look"),
Card(image: UIImage(named: "love")!, soundUrl: "Love"),
Card(image: UIImage(named: "lunch")!, soundUrl: "Lunch")
]
let secondList = [
Card(image: UIImage(named: "lake")!, soundUrl: "Lake"),
Card(image: UIImage(named: "lamb")!, soundUrl: "Lamb"),
Card(image: UIImage(named: "lamp")!, soundUrl: "Lamp"),
Card(image: UIImage(named: "lark")!, soundUrl: "Lark"),
Card(image: UIImage(named: "leaf")!, soundUrl: "Leaf"),
]
override func viewDidLoad() {
super.viewDidLoad()
let list1 = List(words:firstList, active: true)
let list2 = List(words:secondList, active: true)
var imageList: [String]{
let wordLists = [list1, list2]
print((wordLists[0] ).words[0].soundurl)
let active = wordLists.reduce([]) { (result:[String], list:List) in
if list.active {
return result + list.words
} else {
return result
}
}
return active
}
let tapGestureRecognizer = UITapGestureRecognizer(target: self, action: #selector(imageTapped(tapGestureRecognizer:)))
imgPhoto.isUserInteractionEnabled = true
imgPhoto.addGestureRecognizer(tapGestureRecognizer)
imgPhoto.image = (imageList[0] ).image
// Do any additional setup after loading the view.
imgPhoto.isUserInteractionEnabled = true
let leftSwipe = UISwipeGestureRecognizer(target: self, action: #selector(Swiped(gesture:)))
leftSwipe.cancelsTouchesInView = false
let rightSwipe = UISwipeGestureRecognizer(target: self, action: #selector(Swiped(gesture:)))
rightSwipe.cancelsTouchesInView = false
leftSwipe.direction = .left
rightSwipe.direction = .right
view.addGestureRecognizer(leftSwipe)
view.addGestureRecognizer(rightSwipe)
}
@IBAction func imageTapped(tapGestureRecognizer: UITapGestureRecognizer)
{
print("hhh")
imageList[imageIndex].playSound()
// Your action
}
func Swiped(gesture: UIGestureRecognizer) {
if let swipeGesture = gesture as? UISwipeGestureRecognizer {
switch swipeGesture.direction {
case UISwipeGestureRecognizerDirection.right :
print("User swiped right")
// decrease index first
imageIndex -= 1
// check if index is in range
if imageIndex < 0 {
imageIndex = words.count - 1
}
imgPhoto.image = itemList[imageIndex].image
case UISwipeGestureRecognizerDirection.left:
print("User swiped Left")
// increase index first
imageIndex += 1
// check if index is in range
if imageIndex > itemList.count - 1 {
imageIndex = 0
}
imgPhoto.image = itemList[imageIndex].image
default:
break //stops the code/codes nothing.
}
}
}
}
import Foundation; import UIKit; import AVFoundation
var player: AVAudioPlayer?
class Card: NSObject
{
var image: UIImage
var soundUrl: String
init(image: UIImage, soundUrl: String) {
self.image = image
self.soundUrl = soundUrl
}
func playSound()
{ print("play")
guard let url = Bundle.main.url(forResource: self.soundUrl, withExtension: "m4a") else { return }
do
{
try AVAudioSession.sharedInstance().setCategory(AVAudioSessionCategoryPlayback)
try AVAudioSession.sharedInstance().setActive(true)
player = try AVAudioPlayer(contentsOf: url)
guard let player = player else { return }
player.prepareToPlay()
player.play()
print("hhh")
} catch let error {
print(error.localizedDescription)
}
}
}
答案 0 :(得分:0)
result
的类型为[String]
,但list.words
的类型为[Card]
。 Swift不知道你想如何在声明return result + list.words
中将这两者结合起来。
Swift要求您对类型非常具体。因此,当有任何问题时,您需要准确指定所需内容。
您没有显示Card
类型,因此我将为您提供一般示例:
var list1:[String] = ["a", "b", "c"]
var list2:[Any] = ["d", "e", "f"]
let newList = list1 + list2
// error: type of expression is ambiguous without more context
这种组合应该是可能的,因为两个列表都包含String
个值。但是,由于list2
声明它的类型为[Any]
,因此Swift不确定连接的意图。它会给你“模棱两可”的错误。
要解决此问题,您必须具体说明相关类型 - 这意味着您必须根据您希望Swift使用的类型进行转换:
let newList = list1 + (list2 as! [String])
由于list1
已经是[String]
类型,因此Swift现在知道您想要生成[String]
类型。 (在这种情况下,Swift将隐式指定[String]
作为newList
的类型。)
另请注意,您的类型必须兼容才能执行此操作!如果[Card]
不能转换为[String]
,则会收到其他错误。