Question

如果我是第一次运行我的代码，它会成功运行。数据存储在数据库中，http代码为200.如果我在客户端更改了某些数据并尝试再次保存模型，则会出现以下错误。

我在django doc上读过，我可以使用另存为＆＃34;创建＆＃34;和＆＃34;更新＆＃34;同样。

错误消息

heating mapping with this zone already exists

views.py

from heatingControll.models import  HeatingMapping as HeatingMappingModel
 # ... some code ...
    @detail_route(methods="post")
    def save(self, request):
        zone = request.data.get('zone')
        data = json.loads(zone)

        serializer = HeatingMappingSerializer(data=data)

        valid = serializer.is_valid(raise_exception=True)
        if(valid):
           result = serializer.save()
           self.response = {"result": True, "data":HeatingMappingSerializer(result).data, "message": "Erfolgreich gespeichert"}

        return JsonResponse(self.response, safe=False)

zaidfazil支持的解决方案

@detail_route（方法=＆＃34;后＆＃34） def save（self，request）： zone = request.data.get（＆＃39; zone＆＃39;） data = json.loads（zone）

if 'zone' in data:
    obj = HeatingMappingModel.objects.get(id=data.get('id'))
    serializer = HeatingMappingSerializer(data=data, instance=obj)
else:
    serializer = HeatingMappingSerializer(data=data)

valid = serializer.is_valid(raise_exception=True)
if(valid):
   result = serializer.save()
   self.response = {"result": True, "data":HeatingMappingSerializer(result).data, "message": "Erfolgreich gespeichert"}

return JsonResponse(self.response, safe=False)

Answer 1

尝试编辑您的视图，可能是这样，

@detail_route(methods="post")
def save(self, request, pk):
    zone = request.data.get('zone')
    data = json.loads(zone)
    obj = HeatingMapping.objects.get(pk=pk)

    serializer = HeatingMappingSerializer(data=data, instance=obj)

    valid = serializer.is_valid(raise_exception=True)
    if(valid):
       result = serializer.save()
       self.response = {"result": True, "data":HeatingMappingSerializer(result).data, "message": "Erfolgreich gespeichert"}

    return JsonResponse(self.response, safe=False)

如何使用Django Rest Framwork Serializer更新数据库中的模型失败？

1 个答案: